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navik [9.2K]
3 years ago
7

When the pressure that a gas exerts

Chemistry
2 answers:
Mademuasel [1]3 years ago
8 0

Answer:

2.13

Explanation:

Ronch [10]3 years ago
5 0

Answer:

The pressure changes from 2.13 atm to 1.80 atm.

Explanation:

Given data:

Initial pressure = ?

Final pressure = 1.80 atm

Initial temperature = 86.0°C (86.0 + 273 = 359 K)

Final temperature = 30.0°C (30+273 =303 K)

Solution:

According to Gay-Lussac Law,

The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.

Mathematical relationship:

P₁/T₁ = P₂/T₂

Now we will put the values in formula:

P₁ = P₂T₁ /T₂

P₁ = 1.80 atm × 359 K / 303 K

P₁ = 646.2 atm. K /303 K

P₁ = 2.13 atm

The pressure changes from 2.13 atm to 1.80 atm.

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Complete the following equations : H3PO4 = 3H+ --------------- CaSO4 = Ca 2+ ---------------- (2) b) Write the formulae of the s
jeka94

Answer:

H₃PO₄ → 3H⁺ + PO₄³⁻

CaSO₄ → Ca²⁺ + SO₄²⁻

b. CaCl₂

Explanation:

When H₃PO₄ is dissolved in water, there are produced the H⁺ and PO₄³⁻ ions. The equation is:

H₃PO₄ → 3H⁺ + PO₄³⁻

In the same way, CaSO₄ is dissolved in:

CaSO₄ → Ca²⁺ + SO₄²⁻

b. Now, in a reaction of an acid (HCl) and a base (Ca(OH)₂), water, H₂O and a salt are produced:

2 HCl + Ca(OH)₂ → 2H₂O + Salt

The ions that are not present in the reaction are Cl⁻ and Ca²⁺, the salt is CaCl₂ and the balanced reaction is:

2 HCl + Ca(OH)₂ → 2H₂O + CaCl₂

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How does the muscular and nervous system work together to help maitain homeostasis
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The atomic weight of boron is reported as 10.81, yet no atom of boron has the mass of 10.81 amu. explain
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A phosphate buffer is involved in the formation of urine. The developing urine contains H2PO4 and HPO42- in the same concentrati
Katen [24]

Answer:

The ionization equation is

H_{2}PO_{4}^{-}  +H_{2}O ⇄HPO_{4}^{-2}  +H_{3}O^{+} (1)

Explanation:

The ionization equation is

H_{2}PO_{4}^{-}  +H_{2}O ⇄HPO_{4}^{-2}  +H_{3}O^{+} (1)

As the Bronsted definition sais, an acid is a substance with the ability to give protons thus, H2PO4 is the acid and HPO42- is the conjugate base.

The Ka expression is the ratio between the concentration of products and reactants of the equilibrium reaction so,

Ka = \frac{[HPO_{4}^{-2}] [H_{3}O^{+}]}{[H_{2}PO_{4}^{-}] [H_{2}O]} = 6.2x10^{-8}

The pKa is

-Log (Ka) = -Log (6.2x10^{-8}) = 7.2

The pKa of H2CO3 is 6,35, thus this a stronger acid than H2PO4. The higher the pKa of an acid greater the capacity to donate protons.

In the body H2CO3 is a more optimal buffer for regulating pH due to the combination of the two acid-base equilibriums and the two pKa.

If the urine is acidified, according to Le Chatlier's Principle the equilibrium (1)  moves to the left neutralizing the excess proton concentration.

3 0
3 years ago
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