Answer:
Weight % of NH₃ in the aqueous waste = 2.001 %
Explanation:
The chemical equation for the reaction
Moles of HCl = Molarity × Volume
= 0.1039 × 31.89 mL × 
= 0.0033 mole
Total mass of original sample = 25.888 g + 73.464 g
= 99.352 g
Total HCl taken for assay = 
= 0.1083 g
Moles of NH₃ = 
= 0.03047 moles
Mass of NH₃ = number of moles × molar mass
Mass of NH₃ = 0.03047 moles × 17 g
Mass of NH₃ = 0.51799
Weight % of NH₃ = 
%
Weight % of NH₃ in the aqueous waste = 2.001 %
Answer:
O A. A metal higher on the activity series list will replace one that is
lower.
solids have particles that are closely packed to each other that they can barely move
Metalloid is the closest because noble gases are obviously out, nonmetals are terrible conductors, and metals are not malleable
Answer:
The volume of a salt crystal with the mentioned dimensions is V= 107.44 x 10^-8.
Explanation:
To solve this problem we multiply the length of the sides of the crystal. To calculate this product you have to calculate:
1) (5.44 x 2.5 x 9,9). and
2) (10^-2 x 10^-3 x 10^-3). Here we have the product of powers of equal base so we should sum the exponents.
⇒(10^-2 x 10^-3 x 10^-3) = 10^(-2 + -3 + -3) ⇒ (10^-2 x 10^-3 x 10^-3) = 10^-8.
Finally,
V= (5.44 x 10^-2)x (2.3 x 10^-3) x (7.9 x 10^-3) ⇒ V= 107.44 x 10^-8 m.
