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3 years ago

10

A __________ is created by using a secure hash function to generate a hash value for a message and then encrypting the hash code

with a private key.d Group of answer choices

1 answer:

Basile [38]3 years ago

8 0

Answer: Digital signature

Explanation:

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Is electrical conductivity an extensive property or an intensive property?

Thepotemich [5.8K]

Your Answer Will Be Intensive Property

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3 years ago

To what are wax susceptible?

inna [77]

Wax is susceptible to heat. Wax is responds to heat addition. The forces in the wax when heat is added are being broken off and are much lesser as its original state. Hope this answers the question. Have a nice day.<span />

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3 years ago

Which two elements make up the greatest percentages by mass in Earth’s crust?

yuradex [85]

<h2><u>Answer</u> :</h2>

The most appropriate option is :

$\hookrightarrow \bf2. \: \mathrm{ \underline{oxygen \: \: and \: \: silicon}}$

Since, they are the most abundant elements found in Earth's Crust.

Oxygen (46%)

Silicon (28%)

$\circ { \underline{ \boxed{ \sf{ \color{green}{ \mathrm{hope \: \: it \: \: helps \: \: you .....}}}}}}∘$

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2 years ago

Find the enthalpy of neutralization of HCl and NaOH. 137 cm3 of 2.6 mol dm-3 hydrochloric acid was neutralized by 137 cm3 of 2.6

liraira [26]

Answer : The correct option is, (D) 89.39 KJ/mole

Explanation :

First we have to calculate the moles of HCl and NaOH.

$\text{Moles of HCl}=\text{Concentration of HCl}\times \text{Volume of solution}=2.6mole/L\times 0.137L=0.3562mole$

$\text{Moles of NaOH}=\text{Concentration of NaOH}\times \text{Volume of solution}=2.6mole/L\times 0.137L=0.3562mole$

The balanced chemical reaction will be,

$HCl+NaOH\rightarrow NaCl+H_2O$

From the balanced reaction we conclude that,

As, 1 mole of HCl neutralizes by 1 mole of NaOH

So, 0.3562 mole of HCl neutralizes by 0.3562 mole of NaOH

Thus, the number of neutralized moles = 0.3562 mole

Now we have to calculate the mass of water.

As we know that the density of water is 1 g/ml. So, the mass of water will be:

The volume of water = $137ml+137ml=274ml$

$\text{Mass of water}=\text{Density of water}\times \text{Volume of water}=1g/ml\times 274ml=274g$

Now we have to calculate the heat absorbed during the reaction.

$q=m\times c\times (T_{final}-T_{initial})$

where,

q = heat absorbed = ?

$c$ = specific heat of water = $4.18J/g^oC$

m = mass of water = 274 g

$T_{final}$ = final temperature of water = 325.8 K

$T_{initial}$ = initial temperature of metal = 298 K

Now put all the given values in the above formula, we get:

$q=274g\times 4.18J/g^oC\times (325.8-298)K$

$q=31839.896J=31.84KJ$

Thus, the heat released during the neutralization = -31.84 KJ

Now we have to calculate the enthalpy of neutralization.

$\Delta H=\frac{q}{n}$

where,

$\Delta H$ = enthalpy of neutralization = ?

q = heat released = -31.84 KJ

n = number of moles used in neutralization = 0.3562 mole

$\Delta H=\frac{-31.84KJ}{0.3562mole}=-89.39KJ/mole$

The negative sign indicate the heat released during the reaction.

Therefore, the enthalpy of neutralization is, 89.39 KJ/mole

3 0

3 years ago

Theoretical<br> Yield of Cu<br> based on<br> Amount of CuSO4

fiasKO [112]

Answer:

I hope this helps.

Explanation:

6 0

2 years ago