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Hitman42 [59]
3 years ago
13

For the following incomplete combustion reaction, what are the coefficients necessary to balance the equation:

Chemistry
1 answer:
Alexxandr [17]3 years ago
6 0

Answer: A

Explanation:

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Answer:

Those are the answers to an unknown question???

Explanation:

3 0
3 years ago
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An ideal gas (C}R), flowing at 4 kmol/h, expands isothermally at 475 Kfrom 100 to 50 kPa through a rigid device. If the power pr
Zina [86]

<u>Answer:</u> The rate of heat flow is 3.038 kW and the rate of lost work is 1.038 kW.

<u>Explanation:</u>

We are given:

C_p=\frac{7}{2}R\\\\T=475K\\P_1=100kPa\\P_2=50kPa

Rate of flow of ideal gas , n = 4 kmol/hr = \frac{4\times 1000mol}{3600s}=1.11mol/s    (Conversion factors used:  1 kmol = 1000 mol; 1 hr = 3600 s)

Power produced = 2000 W = 2 kW     (Conversion factor:  1 kW = 1000 W)

We know that:

\Delta U=0   (For isothermal process)

So, by applying first law of thermodynamics:

\Delta U=\Delta q-\Delta W

\Delta q=\Delta W      .......(1)

Now, calculating the work done for isothermal process, we use the equation:

\Delta W=nRT\ln (\frac{P_1}{P_2})

where,

\Delta W = change in work done

n = number of moles = 1.11 mol/s

R = Gas constant = 8.314 J/mol.K

T = temperature = 475 K

P_1 = initial pressure = 100 kPa

P_2 = final pressure = 50 kPa

Putting values in above equation, we get:

\Delta W=1.11mol/s\times 8.314J\times 475K\times \ln (\frac{100}{50})\\\\\Delta W=3038.45J/s=3.038kJ/s=3.038kW

Calculating the heat flow, we use equation 1, we get:

[ex]\Delta q=3.038kW[/tex]

Now, calculating the rate of lost work, we use the equation:

\text{Rate of lost work}=\Delta W-\text{Power produced}\\\\\text{Rate of lost work}=(3.038-2)kW\\\text{Rate of lost work}=1.038kW

Hence, the rate of heat flow is 3.038 kW and the rate of lost work is 1.038 kW.

4 0
3 years ago
NaOH has a molarity of 2.5 M and a volume of 4 Liters, how many moles are in<br> the solution?
Inga [223]

Answer:

10. mol NaOH

Explanation:

2.5 M = 2.5 mol/L

2.5 mol/L * 4 L = 10. mol

7 0
3 years ago
Which of the following halogens has the weakest attraction for electrons?
Leokris [45]

Answer:

I

Explanation:

Among the halogens given in this problem, iodine has the lowest attraction for electrons.

This property is known as electronegativity.

Electronegativity is expressed as the relative tendency with which the atoms of the element attracts valence electrons in a chemical bond.

  • As you go down the periodic group the electronegativity decreases.
  • The most electronegative element on the periodic table is fluorine.
  • Down the group, iodine is the least electronegative
  • This is due to the large size of its atom.
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What is another name for a beta minus (B-) particle?
pentagon [3]
<span>electron, I believe.
</span>
6 0
3 years ago
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