Let us assume that even F represents fidelity and event S represents selectivity.
We have been given the probabilities:
P(S) = 0.72, P(F) = 0.59 and 
We need to find the conditional probability that a system with high fidelity will also have high selectivity. We know the conditional probability formula:
Upon substituting the given values, we get:
If x is a real number such that x3 + 4x = 0 then x is 0”.Let q: x is a real number such that x3 + 4x = 0 r: x is 0.i To show that statement p is true we assume that q is true and then show that r is true.Therefore let statement q be true.∴ x2 + 4x = 0 x x2 + 4 = 0⇒ x = 0 or x2+ 4 = 0However since x is real it is 0.Thus statement r is true.Therefore the given statement is true.ii To show statement p to be true by contradiction we assume that p is not true.Let x be a real number such that x3 + 4x = 0 and let x is not 0.Therefore x3 + 4x = 0 x x2+ 4 = 0 x = 0 or x2 + 4 = 0 x = 0 orx2 = – 4However x is real. Therefore x = 0 which is a contradiction since we have assumed that x is not 0.Thus the given statement p is true.iii To prove statement p to be true by contrapositive method we assume that r is false and prove that q must be false.Here r is false implies that it is required to consider the negation of statement r.This obtains the following statement.∼r: x is not 0.It can be seen that x2 + 4 will always be positive.x ≠ 0 implies that the product of any positive real number with x is not zero.Let us consider the product of x with x2 + 4.∴ x x2 + 4 ≠ 0⇒ x3 + 4x ≠ 0This shows that statement q is not true.Thus it has been proved that∼r ⇒∼qTherefore the given statement p is true.
Do you mean 6 to the 5th power. or is there another 6, if so then it would be 6 to the 6th power.
The line rises to the left so the slope is negative.
Slope = rise / run = (3 - 1) / (-4-3) = 2 / -7
Answer is -2/7 (A)
A = (2x + 4)(x^2 - 2)
A = 2x(x^2) + 2x(-2) + 4(x^2) + 4(-2)
A = 2x^3 + -4x + 4x^2 + -8
A = 2x^3 + 4x^2 - 4x - 8
Hope this helps!! :)
