<u>Answer:</u> The mass of glucose in final solution is 0.420 grams
<u>Explanation:</u>
To calculate the molarity of solution, we use the equation:
.........(1)
Initial mass of glucose = 10.5 g
Molar mass of glucose = 180.16 g/mol
Volume of solution = 100 mL
Putting values in equation 1, we get:
To calculate the molarity of the diluted solution, we use the equation:
where,
are the molarity and volume of the concentrated glucose solution
are the molarity and volume of diluted glucose solution
We are given:
Putting values in above equation, we get:
Now, calculating the mass of final glucose solution by using equation 1:
Final molarity of glucose solution = 0.0233 M
Molar mass of glucose = 180.16 g/mol
Volume of solution = 100 mL
Putting values in equation 1, we get:
Hence, the mass of glucose in final solution is 0.420 grams
The sulphate solutions came from a recycling LIBs waste cathode materials, which were done by previous research; their content is shown in Table 1 [18]. Sodium carbonate (Na2CO3) was purchased from Nihon Shiyaku Reagent, Tokyo, Japan (NaCO3, 99.8%), for the chemical precipitation. CO2 was purchased from Air Product and Chemical, Taipei, Taiwan (CO2 ≥ 99%), to carry out the hydrogenation–decomposition method. Dowex G26 was obtained from Sigma-Aldrich (St. Louis, MO, USA) and was used as a strong acidic cation exchange resin, to remove impurities. Multi-elements ICP standard solutions were acquired from AccuStandard, New Haven, Connecticut State, USA. The nitric acid (HNO3) and sulfuric acid (H2SO4) were acquired from Sigma-Aldrich (St. Louis, MO, USA) (HNO3 ≥ 65%) (H2SO4 ≥ 98%) The materials were analyzed by energy-dispersive X-ray spectroscopy (EDS; XFlash6110, Bruker, Billerica, MA, USA), X-ray diffraction (XRD; DX-2700, Dangdong City, Liaoning, China), scanning electron microscopy (SEM; S-3000N, Hitachi, Tokyo, Japan), and inductively coupled plasma optical emission spectrometry (ICP-OES; Varian, Vista-MPX, PerkinElmer, Waltham, MA, USA). In order to
Appl. Sci. 2018, 8, 2252 3 of 10
control the hydrogenation temperature and heating rate, a thermostatic bath (XMtd-204;
Answer:
D.
Explanation:
Hydroxide ions are produced when acid reacts with a base under a Ph value of more than 7. Hydroxide ions are negatively charged ions which are released in the aqueous solution during titration process. It a oxygen and hydrogen atom covalent bond.
Answer:
The solution to the given problem is done below.
Explanation:
a)
i) =( 0.002 μg / L )( 1mg / 1000 μg )( 1L / kg )( 1000 mil / 1 billion) = 0.002 ppb
ii) =( 0.002 μg / L )( 1mg / 1000 μg )( 1L / kg )( 1,000,000 mil / 1 trillion) = 2 ppt
iii) =( 0.002 μg / L )( 1 mole / 540g ) = 3.7 x 
μM.
b)
i) =( 0.002 μg / g ) = 0.002 ppm
ii) In solids, ppb = μg/kg
=( 0.002 μg / g )( 1000 mil/ 1 billion) = 2 ppb
Answer:
Add water to 29.22 grams of salt until you get 1 liter of volume, stir it until the salt completely dissolves and mixes and voila! you will have a 0.5 M NaCl solution.
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