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galina1969 [7]
3 years ago
9

Which of the following statements is TRUE? Which of the following statements is TRUE? Electrons placed in antibonding orbitals s

tabilize the ion/molecule. The total number of molecular orbitals formed doesn't always equal the number of atomic orbitals in the set. When two atomic orbitals come together to form two molecular orbitals, one molecular orbital will be lower in energy than the two separate atomic orbitals and one molecular orbital will be higher in energy than the separate atomic orbitals. A bond order of 0 represents a stable chemical bond. All of the above are true.
Chemistry
1 answer:
marusya05 [52]3 years ago
5 0

Answer:

When two atomic orbitals come together to form two molecular orbitals, one molecular orbital will be lower in energy than the two separate atomic orbitals and one molecular orbital will be higher in energy than the separate atomic orbitals.

Explanation:

<em>Which of the following statements is TRUE? </em>

  • <em>Electrons placed in antibonding orbitals stabilize the ion/molecule.</em> FALSE. Electrons in the antibonding orbitals destabilize the ion/molecule.
  • <em>The total number of molecular orbitals formed doesn't always equal the number of atomic orbitals in the set.</em> FALSE. The total number of molecular orbitals is always equal to the number of atomic orbitals in the set.
  • <em>When two atomic orbitals come together to form two molecular orbitals, one molecular orbital will be lower in energy than the two separate atomic orbitals and one molecular orbital will be higher in energy than the separate atomic orbitals.</em> TRUE. The orbital with lower energy will be the bonding orbital and the one with higher energy will be the antibonding orbital.
  • <em>A bond order of 0 represents a stable chemical bond.</em> FALSE. A chemical bond is stable if the bond order is higher than zero.
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kolbaska11 [484]

Answer:

r = 3.61x10^{-6} M/s

Explanation:

The rate of disappearance (r) is given by the multiplication of the concentrations of the reagents, each one raised of the coefficient of the reaction.

r = k.[S2O2^{-8} ]^{x} x [I^{-} ]^{y}

K is the constant of the reaction, and doesn't depends on the concentrations. First, let's find the coefficients x and y. Let's use the first and the second experiments, and lets divide 1º by 2º :

\frac{r1}{r2} = \frac{0.018^{x} x0.036^{y} }{0.027^xx0.036^y}

\frac{2.6x10^{-6}}{3.9x10^{-6}} = (\frac{0.018}{0.027})^xx(\frac{0.036}{0.036})^y

0.67 = 0.67^x

x = 1

Now, to find the coefficient y let's do the same for the experiments 1 and 3:

\frac{r1}{r3} = \frac{0.018x0.036^y}{0.036x0.054^y}

\frac{2.6x10^{-6}}{7.8x10^{-6}} = (\frac{0.018}{0.036})x(\frac{0.036}{0.054})^y

0.33 = 0.5x 0.67^y

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2.6x10^{-6} = kx0.018x0.036kx6.48x10^{-4} = 2.6x10^{-6}

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Using the data given,

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madreJ [45]

Answer:

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Explanation:

Hello,

In this case, for the dissociation of calcium fluoride:

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