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Alexus [3.1K]
3 years ago
12

A square is cut from a piece of plywood. How can you determine whether the quadrilateral cut out of the plywood is indeed a squa

re? You cannot fold the plywood.
Mathematics
2 answers:
olga nikolaevna [1]3 years ago
8 0

Answer: if all sides are equal lengths and has 4 90 degree angles

MrRa [10]3 years ago
3 0

Answer:

You could get a ruler or measuring stick and measure each side.

There is no guarantee that you can even make a square, since all sides have to be equal though.

Step-by-step explanation:

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What inequality is graphed below?
topjm [15]
The Answer should be D.
4 0
3 years ago
5. Divide 6/3 by 12.<br> A. 1/2<br> B. 12/13<br> C. 13/12<br> D. 9/16
Alex787 [66]
The answer would be A. 1/2
8 0
3 years ago
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A scientist was in a submarine, 52.7 feet below sea level, studying ocean life. Over the next ten minutes, she descended 46.7 fe
Oliga [24]

Answer:

99.4 feet.

Step-by-step explanation:

You'd add 52.7 and 46.7, including 52.7 because she was already 52.7 feet under before she went even deeper.

8 0
3 years ago
Find a solution to the following initial-value problem: dy dx = y(y − 2)e x , y (0) = 1.
Veseljchak [2.6K]

This equation is separable, as

\dfrac{\mathrm dy}{\mathrm dx}=y(y-2)e^x\implies\dfrac{\mathrm dy}{y(y-2)}=e^x\,\mathrm dx

Integrate both sides; on the left, expand the fraction as

\dfrac1{y(y-2)}=\dfrac12\left(\dfrac1{y-2}-\dfrac1y\right)

Then

\displaystyle\int\frac{\mathrm dy}{y(y-2)}=\int e^x\,\mathrm dx\implies\frac12(\ln|y-2|-\ln|y|)=e^x+C

\implies\dfrac12\ln\left|\dfrac{y-2}y\right|=e^x+C

Since y(0)=1, we get

\dfrac12\ln\left|\dfrac{1-2}1\right|=e^0+C\implies C=-1

so that the particular solution is

\dfrac12\ln\left|\dfrac{y-2}y\right|=e^x-1\implies\boxed{y=\dfrac2{1-e^{2e^x-2}}}

4 0
3 years ago
In Lesson 3.05 we discussed comparing the key features of two functions given in different forms. Given the functions below:
Nutka1998 [239]

Answer:

A) f(x) has y-intercept at and g(x) has y-intercept at (0,0)

B) f(x) has asymptote as x= 0 and g(x) has asymptote as x= 4.

Step-by-step explanation:

The functions given are f(x)=\frac{1}{x-3} and the graph of g(x).

A): Since, <em>'y-intercepts are the points where the graph of the function cuts y-axis' </em>

<em>So, 'at x=0, we obtain y-intercepts'.</em>

Thus,

f(0)=\frac{1}{0-3} implies f(0)=\frac{-1}{3}

Hence, (0,\frac{-1}{3}) is the y-intercept of f(x).

Now, we see that,  

The graph of the function g(x) crosses y-axis at the point (0,0).

Hence, the (0,0) is the y-intercept of the function g(x).

B): As we know, <em>'asymptotes are the lines that approaches the curves but does not meet them'. </em>

As, the numerator of f(x) is of lower degree than the denominator.

We have, the function f(x) has x= 0 as the horizontal asymptote.

Further, graph of g(x) gives us, 'the line x= 4 is the asymptote'.

Hence, the function g(x) has vertical line x= 4 as the asymptote.

6 0
3 years ago
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