Question

Who ever helps get branliest.​

Answer 1

Answer:

$\mathrm{A.} \: \frac{5}{14}\cdot \frac{4}{13}$

Step-by-step explanation:

There are 14 marbles in total, of which 5 of them are red. Therefore, the probability that the first marble she chooses is red is $\frac{5}{14}$.

Since she does not replace the marble, there are now 13 marbles in total, of which 4 are red (she drew one of the red marbles on her first draw). Therefore the probability of her drawing a red marble on her second draw is $\frac{4}{13}$, assuming she draws a red marble on the first draw.

Thus, the probability she draws a red marble on both draws is $\fbox{ \mathrm{A.} \: \frac{5}{14}\cdot \frac{4}{13} }$.

Answer 2

Answer:

c ?

Step-by-step explanation: