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Anton [14]
2 years ago
13

A company had 9 x 106 dollars in sales last year. Explain how to find the product 9 x 106​

Mathematics
1 answer:
Temka [501]2 years ago
7 0

Answer:

u multiply 9 X 106 to get ur answer of 954

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assume that a 3 month CD purchased for $2000 pay a simple interest at an annual rate of 10%. How much total interest does it ear
algol [13]
CD = certificate of deposit (an investment)
Interest rate, i = 10% per annum (simple interest)
Principal, P = $2000 (present value)
Period, T = 3 months = 0.25 year

Simple interest formula
Interest earned = Pit
=2000*0.10*0.25
=$50

Balance at maturity (amount that investor gets after three months)
=$2000+$50
=$2050
7 0
3 years ago
What is quartile 1 (Q1)quartile 3 (Q3) and the IQR? Answer all three parts . 13, 23, 24, 25, 26, 26, 37, 47, 47, 48, 50
Fittoniya [83]

Answer:

Quartile 1 (Q1) = 24

Quartile 2 (Q2) = 47

IQR = 23

Step-by-step explanation:

Given:

The set of data are:

13, 23, 24, 25, 26, <u>26</u>, 37, 47, 47, 48, 50

The data are in increasing order. The number terms are, n = 11.

Therefore, the middle term = \frac{n+1}{2}=\frac{11+1}{2}=6^{th}\ term

So, the median = 26

Now, the median divides the set of data into two parts. The median of first part is the quartile 1 and the median of second part is quartile 2.

So, the first part has the following terms:

13, 23, <u>24</u>, 25, 26

Here also, n=5. So, the third term is the median.

∴ Q1 = 24

The second part has the following terms:

37, 47, <u>47</u>, 48, 50

Here also, n=5. So, the third term is the median.

∴ Q2 = 47.

Now, IQR = Q2 - Q1 = 47 - 24 = 23.

7 0
3 years ago
Solve:<br><br><img src="https://tex.z-dn.net/?f=%5Cunderset%7Bx%5Crightarrow~3%7D%7B%5Clim%7D~%5Cdfrac%7B2x%5E2-18%7D%7Bx%5E2-3x
vodomira [7]

Hello, please consider the following.

\displaystyle \lim_{x\rightarrow3}~\dfrac{2x^2-18}{x^2-3x} \\ \\ \\ =\lim_{x\rightarrow3}~\dfrac{2(x^2-3^2)}{x(x-3)} \\ \\ \\ =\lim_{x\rightarrow3}~\dfrac{2(x-3)(x+3)}{x(x-3)} \\ \\ \\ =\lim_{x\rightarrow3}~\dfrac{2(x+3)}{x} \\ \\ \\=\dfrac{2(3+3)}{3}\\ \\ \\=\dfrac{2*3*2}{3} =\Large \boxed{\sf \bf \ 4 \ }

Thank you

8 0
3 years ago
A farmer uses a lever to move a large rock. The force required to move the rock varies inversely with the distance from the pivo
zaharov [31]

Answer:f=1800/d Inverse proportion function. Provided f is in pounds & d is in inches.

Step-by-step explanation: the relationship between f & d is inverse proportion.

A constant k has to be derived from the relationship.

If f is inversely proportional to d then f=k(1/d)

K= f X d

= 50 X 36

=> constant K=1800.

8 0
2 years ago
A teacher categorized students by whether they regularly completed their homework (or not) and whether they passed the course (o
ella [17]

Probabilities are used to determine the chances of an event.

Let P represents the event that a student passes the course, and C represents the event that a student completes the assignment

<u />

<u>(a) The probability a student passed the course given that they completed their homework?</u>

From the table, we have:

\mathbf{n(P\ n\ C) = 25}

\mathbf{n(C) = 30}

So, the required probability is:

\mathbf{Pr = \frac{n(P\ n\ C)}{n(C)}}

This gives

\mathbf{Pr = \frac{25}{30}}

\mathbf{Pr = 0.8333}

Express as percentage

\mathbf{Pr = 83.33\%}

Hence, the probability a student passed the course given that they completed their homework is 83.33%

<u>(b) The probability a student passed the course given that they didn't complete their homework</u>

From the table, we have:

\mathbf{n(P\ n\ C'= 7}

\mathbf{n(C') = 25}

So, the required probability is:

\mathbf{Pr = \frac{n(P\ n\ C')}{n(C')}}

This gives

\mathbf{Pr = \frac{7}{25}}

\mathbf{Pr = 0.28}

Express as percentage

\mathbf{Pr = 28\%}

Hence, the probability a student passed the course given that they didn't complete their homework is 28%

<u>(c) The probability a student completed their homework given that passed the course?</u>

From the table, we have:

\mathbf{n(P\ n\ C) = 25}

\mathbf{n(P) = 32}

So, the required probability is:

\mathbf{Pr = \frac{n(P\ n\ C)}{n(P)}}

This gives

\mathbf{Pr = \frac{25}{32}}

\mathbf{Pr = 0.78125}

Express as percentage

\mathbf{Pr = 78.125\%}

Approximate

\mathbf{Pr = 78.13\%}

Hence, the probability a student completed their homework given that they passed the course is 78.13%

<u>(d) The probability a student didn't complete their homework given that they didn't pass the course </u>

From the table, we have:

\mathbf{n(P'\ n\ C'= 18}

\mathbf{n(P) = 23}

So, the required probability is:

\mathbf{Pr = \frac{n(P'\ n\ C')}{n(P')}}

This gives

\mathbf{Pr = \frac{18}{23}}

\mathbf{Pr = 0.7826}

Express as percentage

\mathbf{Pr = 78.26\%}

Hence, the probability a student didn't complete their homework given that they didn't pass the course is 78.26%

Read more about probabilities at:

brainly.com/question/11234923

7 0
2 years ago
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