What data will you collect in order to calculate the balloon car’s velocity?
1 answer:
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3s
Explanation:
Given parameters:
Mass of car = 1000kg
Force applied = 8000N
speed = 24m/s
Unknown:
time taken for the car to stop = ?
Solution:
According to newton's second law of motion; "the force on a body is the product of its mass and acceleration".
Force = mass x acceleration
let us find the acceleration of the car;
a = =
= 8m/s²
since the car is accelerating at a rate of 8m/s², when the brakes are applied, it will start decelerating at the constant rate, - 8m/s²
Applying the appropriate equation of motion;
V = U + at
V is the final velocity
U is the initial velocity
a is the acceleration
t is the time taken
final velocity = 0
0 = U + at
-U = at
-24 = -8t
t = 3s
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Answer:
x(t)=0.337sin((5.929t)
Explanation:
A frictionless spring with a 3-kg mass can be held stretched 1.6 meters beyond its natural length by a force of 90 newtons. If the spring begins at its equilibrium position, but a push gives it an initial velocity of 2 m/sec, find the position of the mass after t seconds.
Solution. Let x(t) denote the position of the mass at time t. Then x satisfies the differential equation
Definition of parameters
m=mass 3kg
k=force constant
e=extension ,m
ω =angular frequency
k=90/1.6=56.25N/m
ω^2=k/m= 56.25/1.6
ω^2=35.15625
ω=5.929
General solution will be
differentiating x(t)
dx(t)=-5.929c1sin(5.929t)+5.929c2cos(5.929t)
when x(0)=0, gives c1=0
dx(t0)=2m/s gives c2=0.337
Therefore, the position of the mass after t seconds is
x(t)=0.337sin((5.929t)