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SCORPION-xisa [38]
4 years ago
8

What statement is NOT true about standard electrode potentials?

Physics
1 answer:
creativ13 [48]4 years ago
4 0

Answer:

(a) E^{\circ}_{cell}  is the difference in voltage between the anode and the cathode .

Explanation:

If E^{\circ}_{cell} will be the difference anode and the cathode means E^{\circ}_{cell}=E^{\circ}_{anode}-E^{\circ}_{cathode}n as we know that cathode potential is greater than the anode potential so E^{\circ}_{cell} will become negative and if E^{\circ}_{cell}  is negative then reaction will not be spontaneous so the correct relation of  E^{\circ}_{cell} is E^{\circ}_{cell}=E^{\circ}_{cathode}-E^{\circ}_{anode}

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Answer:

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Why would the measurements have to take place around the same time every day
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ASHA 777 [7]

The charge would be in equilibrium so there would be no charge in the body of the conductor.


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Light travels at a speed of about 3.0 108 m/s. (a) how many miles does a pulse of light travel in a time interval of 0.1 s, whic
babunello [35]

Speed of light is given as

c = 3 * 10^8 m/s

time interval is given as

\Delta t = 0.1 s

so the distance covered by the light is given as

d = v * \Delta t

d = 3 * 10^8 * 0.1 = 3 * 10^7 meter

now as we know that

1 mile = 1609 meter

so the distance moved by light is

d = \frac{3 * 10^7}{1609} = 18645.12 miles

now for the comparision of this distance with diameter of earth

as we know that radius of earth is

R = 6.38 * 10^6 m

so the diameter of earth will be

d = 2R = 12.76 * 10^6 m

now the ratio of diameter with the distance that light move will be

\frac{distance}{diameter} = \frac{3 * 10^7}{12.76 * 10^6}

\frac{distance}{diameter} = 2.35

<em>so it is 2.35 times more than the diameter of earth</em>

4 0
3 years ago
A science-fiction tale describes an artificial "planet" in the form of a band completely encircling a sun. The inhabitants live
arlik [135]

Answer:

8.97 days

Explanation:

Assuming we are asked what will be the period of revolution, this planet's year, in Earth days?

The period of revolution T is given as

T=2\pi\sqrt{\frac{r}{g} }

here, r= distance between planet and its sun which is same as distance between Earth-Sun = 149.7\times10^9 m

g= acceleration due to gravity = 9.81 m/s^2

therefore,

T=2\pi\sqrt{\frac{149.7\times10^9}{9.81} }

=775580 seconds

= 8.97 days

6 0
4 years ago
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