3 years ago

What two characteristics are used to classify air masses

Physics

1 answer:

IgorLugansk [536]3 years ago

7 0

Answer: Temperature and humidity are the two characteristics used to classify air masses.

Explanation:

You might be interested in

How physical science can be truth?

JulsSmile [24]

Because it is physically true day really know that by just knowing it very well

4 0

3 years ago

A horizontal spring with spring constant 85 N/m extends outward from a wall just above floor level. A 5.5 kg box sliding across

Aloiza [94]

Answer: The box was moving with a velocity of 0.256m/s when it hit the spring

Explanation: Please see the attachments below

6 0

3 years ago

If the center of mass passes outside the area of support of an object, what will happen to it?

defon

Answer:

If a vertical line extending down from an object's CG extends outside its area of support, the object will topple

Explanation:

We can understand better this situation using a diagram with the forces acting on it.

In the attached image we can see that when the gravity center is bouncing outside from the area of the pedestal, the object will be out of balance and will fall.

6 0

3 years ago

Lightning produces a maximum air temperature on the order of 104K, whereas a nuclear explosion produces a temperature on the ord

gtnhenbr [62]

Answer:

tex]2.898\times 10^{-7}\ \text{m}[/tex] ultraviolet region

$2.898\times 10^{-10}\ \text{m}$ x-ray region

Explanation:

T = Temperature

b = Constant of proportionality = $2.898\times 10^{-3}\ \text{m K}$

$\lambda$ = Wavelength

$T=10^4\ \text{K}$

From Wein's law we have

$\lambda=\dfrac{b}{T}\\\Rightarrow \lambda=\dfrac{2.898\times 10^{-3}}{10^4}\\\Rightarrow \lambda=2.898\times 10^{-7}\ \text{m}$

The wavelength of the radiation will be $2.898\times 10^{-7}\ \text{m}$ and it is in the ultraviolet region.

$T=10^7\ \text{K}$

$\lambda=\dfrac{2.898\times 10^{-3}}{10^7}\\\Rightarrow \lambda=2.898\times 10^{-10}\ \text{m}$

The wavelength of the radiation will be $2.898\times 10^{-10}\ \text{m}$ and it is in the x-ray region.

5 0

3 years ago

What is the impulse of a 2 kg object that starts at 10 m/s and comes to a stop over 0.4 seconds?

gizmo_the_mogwai [7]

Answer: Impulse = 20 Ns

Explanation:

Impulse is the product of force and time

Also impulse = momentum

Where momentum is the product of mass and velocity.

Given that

M = 2kg

V = 10 m/s

Impulse = MV = 2 × 10 = 20 Ns

8 0

3 years ago