All categories

3 years ago

What two characteristics are used to classify air masses

Physics

1 answer:

IgorLugansk [536]3 years ago

7 0

Answer: Temperature and humidity are the two characteristics used to classify air masses.

Explanation:

You might be interested in

New seafloor is being created at point ______________. 1. X 2. Y 3. Z 4. None

lawyer [7]

Answer:

Point x I think

Explanation:

8 0

2 years ago

A 900 kg vehicle moves around a curve with an incline of 20\circ∘ at a speed of 12.5 m/s. If the curve has a radius of 50 meters

valentina_108 [34]

Answer:

The normal force experienced by the car is approximately 8223.2 N

Explanation:

The question relates to banking of road where the centripetal force for the circular motion of the vehicle is provided by the horizontal component of the normal reaction

The mass of the vehicle that moves around the curve, m = 900 kg

The incline of the curve, θ = 20°

The speed with which the vehicle moves around the curve, v = 12.5 m/s

The radius of the curve, R = 50 meters

We have;

$N \cdot sin(\theta) = \dfrac{m \cdot v^2}{R}$

Where;

θ = The angle of inclination of the road = 20°

N = The normal force experienced by the car

m = The mass of the car = 900 kg

v = The velocity with which the car is moving = 12.5 m/s

R = The radius of the curve around which the vehicle moves = 50 m

$\therefore N = \dfrac{m \cdot v^2}{R \cdot sin(\theta)} = \dfrac{900 \times (12.5)^2}{50 \times sin(20^{\circ})} = 8223.1998754586828969046217875927$

The normal force experienced by the car = N ≈ 8223.2 N.

6 0

2 years ago

A boat traveling at a velocity of 20 m/s leaves island heading east . The boat slows to rest at a rate of 1.5 m/s2 How far away

ioda

The boat's initial velocity is:

$v_0 = 20 m/s$

While the boat's acceleration is

$a=-1.5 m/s^2$

with a negative sign, since the boat is slowing down, so it is a deceleration. The distance traveled by the boat until it comes to a stop can be found by using the following equation:

$v_f^2 -v_0^2 = 2aS$

where vf=0 is the final velocity of the boat and S is the distance covered. Re-arranging the formula, we can find S:

$S=\frac{-v_0^2}{2a}=\frac{-(20 m/s)^2}{2(-1.5 m/s^2)}=133.3 m$

7 0

2 years ago

The magnitude of vector λa is 5. Find the value of λ, if: a = (−6, 8)

Nata [24]

Given :

$\: \:$

$\color{pink}{\rm \: The \:magnitude \:of \:vector\: λa\: is \: {\bold5\:}}$

$\:$

$\color{green}{\rm \: a = (−6, 8)}$

$\:$

To Find :

$\: \:$

$\orange{ \rm\: value \: of \: \bold{ λ \: }}$

$\: \:$

$\rm \: The \: magnitude \: of \: the \: vector \: a \: is \: ||a|| = \sqrt{(-6)^2+ 8^2)} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \rm = \sqrt{( 36+64)} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:\:\: \: \:\:= \rm\sqrt{100} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:\\\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:\: \rm \underline{\boxed{\red{ \: = 10 \: }}} \green✓$

$\: \:$

$\rm \: Therefore, \: λ = \cancel{\frac{5}{10} } \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \underline { \: \boxed{ \red{\: \rm = 0.5\:}}}{ \green ✓ }$

Hope helps ~

$\color{purple}\frak{SarcasticSmileeᥫ᭡}$

4 0

2 years ago

I’m done with Brainly so I’m giving out my points #5

pshichka [43]

Answer:

okay, thanks again

Explanation:

6 0

3 years ago

Read 2 more answers