Answer:
0.339 kgm²
Explanation:
We know the period of this pendulum, T = 2π√(I/mgh) where I = moment of inertia of the object about the pivot axis, m = mass of object = 2.15 kg, g = acceleration due to gravity = 9.8 m/s² and h = distance of center of mass of object from pivot point = 0.163 m.
Since T = 2π√(I/mgh), making I subject of the formula, we have
I = mghT²/4π²
Now since it takes 241 s to complete 113 cycles, then it takes 241 s/113 cycles to complete one cycle.
So, T = 241 s/113 = 2.133 s
So, Substituting the values of the variables into I, we have
I = mghT²/4π²
I = 2.15 kg × 9.8 m/s² × 0.163 m × (2.133 s)²/4π²
I = 15.63/4π² kgm²
I = 0.396 kgm²
Now from the parallel axis theorem, I = I' + mh² where I' = moment of inertia of object with respect to its center of mass about an axis parallel to the pivot axis
I' = I - mh²
I' = 0.396 kgm² - 2.15 kg × (0.163 m)²
I' = 0.396 kgm² - 0.057 kgm²
I' = 0.339 kgm²
The answer would be no. Both will have same charge, in both caes charge will reside on surface. In case of solid sphere it will be distributed evenly throughout. Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.
An elliptical galaxy is a type of galaxy having an approximately ellipsoidal shape and a smooth, nearly featureless brightness profile.
Unlike flat spiral galaxies with organization and structure, they are more three-dimensional, without much structure, and their stars are in somewhat random orbits around the center.
Answer:
1660 V
Explanation:
Resistance should be determined and then voltage drop across the power line can be determined.
R = ρ L /A
Here ρ = Resistivity of aluminum = 
L = length = 32 km = 32,000 m
Area of cross section = A = π r² = π (0.027/2)² = 0.00057255 m²
Resistance = R =
( (32,000)/(0.00057255) = 1.5090 Ohms.
Voltage drop = V = I R = (1100)(1.5090) = 1659.9 V.
(If resistivity value is different, then the resistance will be different and hence final answer for voltage will also vary ).
