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dybincka [34]
3 years ago
8

An aircraft has a liftoff speed of 33 m/s. What is the minimum constant acceleration an

Physics
1 answer:
JulsSmile [24]3 years ago
5 0

Answer: The minimum acceleration for the air plane is 2.269m/s2.

Explanation: To solve such problem the equation of motion are applicable.

The initial velocity is 0 since the airplane was initially standing. We are going to use this equation

V^2=U^2+2as

33^2=0+2a (240)

a= 2.269m/s2

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A particle is moving in a circle of diameter 5. calculate the distance covered and the displacement when it completes 3 revoluti
Mamont248 [21]

Total distance covered is 47.1 m whereas displacement is zero.

<h3>Calculation:</h3>

Given,

Diameter, d = 5 m

No. of revolutions = 3

Radius, r = 5/2 = 2.5 m

To find,

Distance =?

Displacement =?

Distance covered in one revolution = 2πr

                                                           

Put the values in this,

Distance = 2 × 3.14 × 2.5

               = 15.7 m

Total distance covered in 3 revolution = 3 × 31.4

                                                                = 47.1 m

Displacement is the change in the position of the object or the distance between the initial and final position.

After 3 revolutions the particle comes back to its initial position. Therefore, the displacement is zero.

Hence, the total distance covered in 3 resolutions is 47.1 m whereas displacement is zero.

Learn more about distance and displacement here:

brainly.com/question/3243551

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5 0
1 year ago
Please help me out !!
blagie [28]
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Answer:

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