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Allisa [31]
3 years ago
14

Why are bridges declared unsafe after a long use​

Physics
1 answer:
lina2011 [118]3 years ago
8 0

After it's long use, the bridge continuously undergoes through alternating strains. in result, the elastic strength of the bridge gets reduced. while the process goes on the bridge makes elastic fatigue and a permanent change happens which makes it collapse which is the reason why bridges are declared unsafe after a long use​ :)

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Your friend says that inertia is a force that keeps things in their place, either at rest or in motion. Do you and your discussi
Galina-37 [17]

Answer:

yes i agree

Explanation:

because law of inertia state that object remain at rest or in motion unless external force apply on it

8 0
3 years ago
A body weighs 100newtons when submerged in water. calculate the upthrust action on the body​
Andrews [41]

Answer:

Upthrust = 20 N

Explanation:

The question says that "A body weighs 100N in air and 80N when submerged in water. Calculate the upthrust acting on the body ?"

Upthrust is defined as the force when a body is submerged in liquid, then liquid applies a force on it.

ATQ,

Weight of body in air is 100 N

Weight of body in water is 80 N

Upthrust is equal to the weight of body in air minus weight of body in water.

Upthrust = 100 N - 80 N

Upthrust = 20 N

So, 20 N of upthrust is acting on the body.

7 0
3 years ago
can someone help me answer this question? A student connected an ammeter as shown in this picture. Did the student connect the a
nalin [4]

Answer:

No - It is connected in parallel instead of series

Explanation:

4 0
2 years ago
Problem I Marcella (see warmup problem, above) gets her car moving steadily at 4m/s but suddenly someone stops ahead to assist h
Nady [450]

Answer:

Explanation:

a) KE = (1/2) * m * (v^{2}) = F * d = 14m * 200N = 2800 m/N or 2.8 * 10^{3} m/N

b) 0J and 0m/s (if Marcella stopped after going 14 meters)

c)  Known from part (a) that KE = 2800 J = F1 * d1,

    2800J = F1 * (14m - 1m)  => F1 = 2800J/13m = 215.384 N

   

3 0
3 years ago
Assume that the Deschutes River has straight and parallel banks and that the current is 0.75 m/s. Drifting down the river, you f
DedPeter [7]

Answer:

    d = 142.5 m

Explanation:

This is a vector exercise. Let's calculate how much the boat travels in the 40s

     d₀ = v_{b} t

    d₀ = 0.75 40

    d₀ = 30 m

Let's write the kinematic equations

Boat

     x = d₀  +  v_{b} t

     x = 0 +  v_{h} t

At the meeting point the coordinate is the same for both

    d₀  +  v_{b} t =  v_{h} t

    t ( v_{h} -  v_{b}) = d₀  

    t = d₀  / ( v_{b}-  v_{h})

The two go in the same direction therefore the speeds have the same sign

     t = 30 / (0.95-0.775)

     t = 150 s

The distance traveled by man is

     d =  v_{h} t

     d = 0.95 150

     d = 142.5 m

3 0
3 years ago
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