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Dimas [21]
2 years ago
8

I need help wit dis it is going in as a test grade

Mathematics
2 answers:
Deffense [45]2 years ago
6 0

Answer:

A: -51

Step-by-step explanation:

You are welcome...

Ksju [112]2 years ago
4 0

Answer:

B, I think

Step-by-step explanation:

You might be interested in
(-4^0) + 1 equals to ?​
Mama L [17]

Answer:

zero (0)

Step-by-step explanation:

-4^0=-1

-1+1=0

6 0
2 years ago
HELP ASAP PLEASE!
tatyana61 [14]
M= (y2-y1)/(x2-x1)

Plug in the points. (2,3) (9,7)

m= (7-3)/(9-2)

m= 4/7

Slope= 4/7

I hope this helps!
~kaikers
7 0
2 years ago
The square root of 9x^3/5y^2 show your work. (Do not forget to rationalize the denominator)
Maslowich

Answer:

I believe it would be 9.

9–√2

=3

All roots:

3

−3

9 is a perfect square

5 0
3 years ago
Find a function where f(0)=2 and f(1)=2
xenn [34]

Answer:

Do you want to be extremely boring?

Since the value is 2 at both 0 and 1, why not make it so the value is 2 everywhere else?

f(x) = 2 is a valid solution.

Want something more fun? Why not a parabola? f(x)= ax^2+bx+c.

At this point you have three parameters to play with, and from the fact that f(0)=2 we can already fix one of them, in particular c=2. At this point I would recommend picking an easy value for one of the two, let's say a= 1 (or even a=-1, it will just flip everything upside down) and find out b accordingly:f(1)=2 \rightarrow 1^2+b+2=2 \rightarrow b=-1

Our function becomes

f(x) = x^2-x+2

Notice that it works even by switching sign in the first two terms: f(x) = -x^2+x+2

Want something even more creative? Try playing with a cosine tweaking it's amplitude and frequency so that it's period goes to 1 and it's amplitude gets to 2: f(x) = A cos (kx)

Since cosine is bound between -1 and 1, in order to reach the maximum at 2 we need A= 2, and at that point the first condition is guaranteed; using the second to find k we get 2= 2 cos (k1) = cos k = 1 \rightarrow k = 2\pi

f(x) = 2cos(2\pi x)

Or how about a sine wave that oscillates around 2? with a similar reasoning you get

f(x)= 2+sin(2\pi x)

Sky is the limit.

8 0
2 years ago
What is the square root of 9/16, 9 to the power of two
lbvjy [14]

Answer:

\frac{3}{4} , 9

Step-by-step explanation:

\sqrt{9/16} = \sqrt{9} ÷ \sqrt{16} = \frac{3}{4}

\sqrt{9^2} = \sqrt{81} = 9


3 0
3 years ago
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