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3 years ago

When a fair coin is ossed 4 times what is probability of tossing at least 3 heads?

Mathematics

1 answer:

creativ13 [48]3 years ago

7 0

The ratio of that probability is 3 : 4

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Solve the following system of equations.

krek1111 [17]

The answer is B.

The attached file is how I got the answer.

Hope this helped :)

5 0

2 years ago

What are five qualities of an entrepreneur that you can use to help you navigate the ""new normal ""

9966 [12]

Answer:

Risk taking

Vision driven

Passionate

Goal oriented

Decision maker.

Step-by-step explanation:

An entrepreneur is a person who sets up a business, manages it and work towards maximizing profit.

In order to be able to navigate the "new normal", these five qualities are very essential in an entrepreneur if he/she wishes to go far.

6 0

2 years ago

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You roll a 6-sided die with faces numbered 1 through 6, and toss a coin. What is the probability of rolling a 2 or getting heads

valentina_108 [34]

That sounds like an extremely misleading question to me but it would be A since theres a 1/6 chance of getting a 2 on a die and there isnt a 1/2 in the answers so it is A

5 0

3 years ago

Read 2 more answers

How do you solve 3x^6- 39x^4+ 108x^2= 0

ArbitrLikvidat [17]

You can first take out an x^2 from each number , 3x^6 - 39x^4 + 108x^2 = x^2 ( 3x^4 - 39x^2 + 108) Then just factor and solve for the zero's of the equation

6 0

3 years ago

Two events, A and B, are independent of each other. P(A)=– and P(A and B)

Georgia [21]

Answer:

D: 0.75

$P(B) = \frac{6}{8} = 0.75$

Step-by-step explanation:

Explanation:-

Independent events:

If the occurrence of the event 'B' is not effected by the occurrence or non- occurrence of the event 'A' then the event 'B' is said to be independent of 'A'

The two events are independent if the incidence of one event is not affect the probability of other event.

P(A∩B) = P(A) P(B)

Given data A and B are independent events

Given data

$P(AnB) = \frac{1}{8} and P(A) =\frac{1}{6}$

we know that A and B are independent events are

P(A∩B) = P(A) P(B)

$\frac{1}{8} = \frac{1}{6} P(B)$

Now calculation we get

$P(B) = \frac{6}{8} = 0.75$

Final answer:-

$P(B) = \frac{6}{8} = 0.75$

7 0

3 years ago