Answer:
0.128 g
Explanation:
Given data:
Volume of gas = 146.7 cm³
Pressure of gas = 106.5 Kpa
Temperature of gas = 167°C
Mass of oxygen gas = ?
Solution:
Volume of gas = 146.7 cm³ (146.7 /1000 = 0.1467 L)
Pressure of gas = 106.5 Kpa (106.5/101 = 1.1 atm)
Temperature of gas = 167°C (167 +273.15 = 440.15 K)
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
n = PV/RT
n = 1.1 atm× 0.1467 L / 0.0821 atm.L/ mol.K × 440.15 K
n = 0.1614 / 36.14 /mol
n = 0.004 mol
Mass of oxygen:
Mass = number of moles × molar mass
Mass = 0.004 mol × 32 g/mol
Mass = 0.128 g
Answer:
Oxygen and Carbon are in the non-metal section. Both are in 2nd period while Carbon is in group 4A and Oxygen is in group 6A.
Oxygen has more valence electrons than carbon. I wish I could give you a more accurate explanation why on paper, but all you need to do is count the electrons on the largest shell.
Here's the orbital notation of Carbon: 1s^2 2s^2 2px^1 py^1
Carbon's largest shell is 2. Count the electrons on shell 2, and you get 4 valence electrons.
Orbital notation of Oxygen: 1s^2 2s^2 2px^2 py^1 pz^1
Oxygen's largest shell is 2. So, like with carbon, count the electrons on the largest shell. You get 6.
There is a way easier way of interpreting this where you do not even have to write the orbital notation. I wish I can explain, but just know the periods and the group numbers.
Answer:
Two or more elements combined into one substance through a chemical reaction, such as water, form a chemical compound.Compounds made primarily of carbon and hydrogen atoms are called organic compounds, and all others are called inorganic compounds.
HOPE THIS HELPED!!!!!!!!!!!!XDDDDD
Wavelength of the light is 2.9 × 10⁻⁷ m.
<u>Explanation:</u>
Planck - Einstein equation shows the relationship between the energy of a photon and its frequency, and they are directly proportional to each other and it is given by the equation as E = hν,
where E is the energy of the photon
h is the Planck's constant = 6.626 × 10⁻³⁴ J s
ν is the frequency
From the above equation, we can find the frequency by rearranging the equation as,
ν = 
= 
Now the frequency and the wavelength are in inverse relationship with each other.
ν × λ = c
It can be rearranged to get λ as,
λ = c / ν
= 
So wavelength is 2.9 × 10⁻⁷ m.
