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nikitadnepr [17]
2 years ago
13

5. Consider the following experiment: A block of iron with an initial mass of 50 g is placed in a sealed container of pure oxyge

n. After several days, the block is red in color and has a mass of 74 g. Are these observations a violation of the law of conservation of mass? Justify your answer.
Chemistry
1 answer:
Vera_Pavlovna [14]2 years ago
8 0

The observation in the illustration remains in accordance with the law of conservation of mass assuming that moisture is present in the container.

<h3>What is the law of conservation of mass?</h3>

The law state that mass can neither be created nor destroyed. However, mass can be converted from one form to another.

In this case, the ion was placed in a container of pure oxygen. Assuming that moisture is present, iron reacts with oxygen to form rust according to the following equation:

4Fe + 3O_2 + 6H_2O --- > 4Fe(OH)_3

The rust formed will weigh more than the initial weight of the iron.

Without the presence of moisture, one can effectively conclude that the observation violates the law of conservation of mass.

More on the law of conservation of mass can be found here: brainly.com/question/13383562

#SPJ1

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Which phrase describes the molarity of a solution?
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6 0
3 years ago
Assuming an efficiency of 30.80%, calculate the actual yield of magnesium nitrate formed from 147.4g of magnesium and excess cop
Reil [10]

Answer:

The answer to your question is 280 g of Mg(NO₃)₂

Explanation:

Data

Efficiency = 30.80 %

Mg(NO₃)₂ = ?

Magnesium = 147.4 g

Copper (II) nitrate = excess

Balanced Reaction

                     Mg  +   Cu(NO₃)₂    ⇒    Mg(NO₃)₂   +   Cu

                  Reactants           Elements            Products

                         1                          Mg                     1

                         1                          Cu                      1

                         2                          N                       2

                         6                          O                       6

Process

1.- Calculate the theoretical yield

Molecular weight Mg = 24

Molecular weight Mg(NO₃)₂ = 24 + (14 x 2) + (16 x 6)

                                              = 24 + 28 + 96

                                              = 148 g

                           24 g of Mg  --------------------  148 g of Mg(NO₃)₂

                          147.4 g of Mg -------------------   x

                            x = (147.4 x 148) / 24

                            x = 908.96 g of Mg(NO₃)₂

2.- Calculate the Actual yield

yield percent = \frac{actual yield}{theoretical yield}

Solve for actual yield

Actual yield = Yield percent x Theoretical yield

Substitution

Actual yield = \frac{30.8}{100} x 908.96

Actual yield = 279.95 ≈ 280g

                     

4 0
3 years ago
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