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dem82 [27]
3 years ago
12

A gas-forming reaction produces 1.15 m 3 of gas against a constant pressure of 102.0 kPa. Calculate the work done by the gas in

joules.
Chemistry
1 answer:
Aleonysh [2.5K]3 years ago
8 0

Answer:

The work done by the gas is 117,300 Joules.

Explanation:

Pressure applied on the gas , P= 102.0 kPa = 102000 Pa ( 1kPa = 1000 Pa

Change in volume of the gas ,ΔV= 1.15 m^3

Here the work is done by system so, the value of work done will be negative.

W=-P\Delta V

=W=-102000 Pa\times 1.15 m^3=117,300 J

The work done by the gas is 117,300 Joules.

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6) (a) Calculate the absorbance of the solution if its concentration is 0.0278 M and its molar extinction coefficient is 35.9 L/
Anvisha [2.4K]

Answer:

6) (a) 0.499; (b) 31.7 %

7) 0.15

Explanation:

6) (a) Absorbance

Beer's Law is

A = \epsilon cl\\A = \text{35.9 L&\cdot$mol$^{-1}$cm$^{-1}$} $\times$ 0.0278 mol$\cdot$L$^{-1} \times $ 0.5 cm = \mathbf{0.499}

(b) Percent transmission

A = \log {\left (\dfrac{1}{T}}\right)}\\\\\%T = 100T\\\\T = \dfrac{\%T}{100}\\\\\dfrac{1}{T} = \dfrac{100 }{\%T}\\\\A = \log \left(\dfrac{100 }{\%T} \right ) = 2 - \log \%T\\\\0.499 = 2 - \log \%T\\\\\log \%T = 2 - 0.499 = 1.501\\\\\%T = 10^{1.501} = \mathbf{31.7}

7) Absorbance

A = \log \left (\dfrac{I_{0}}{I} \right ) = \log \left (\dfrac{I_{0}}{0.70I_{0}} \right ) = \log \left (\dfrac{1}{0.70} \right ) = -\log(0.70) = \mathbf{0.15}}

8 0
3 years ago
Which are homogeneous mixtures? check all that apply
marishachu [46]

Answer:

isk tbh,

Explanation:

5 0
3 years ago
Read 2 more answers
3- Fully folded proteins typically have polar side chains on their surfaces, where electrostatic attractions and hydrogen bonds
Elden [556K]

Answer:

Option C= A hydrogen bond formed between a polar side chain and a hydrophobic side chain.

Explanation:

All three given options a, b and d have common mechanism to accommodate the polar amino acid.

A= A hydrogen bond forms between two polar side chains.

B= A hydrogen bond from between a polar side chain and protein back bone.

D =  hydrogen bond form between polar side chains and a buried water molecules.

All these are use to accommodate the polar amino acid.

While option C is not used. which is:

A hydrogen bond formed between a polar side chain and a hydrophobic side chain.

5 0
3 years ago
Any one know the answer?
quester [9]
The last one, answer is D
8 0
3 years ago
HELP ASAP PLZ!!!! Find the mass of each substance. Show your work.
Gemiola [76]

Answer:

A. m C5H12 = 108.23 g

B. m F2 = 547.142 g

C. m Ca(CN)2 = 71.85 g

Explanation:

  • mass (m) = mol (n) × molecular weigth (Mw)

∴ Mw C5H12 = ((12.011)(5)) + ((1.008)(12)) = 72.151 g/mol C5H12

∴ Mw F2 = (18.998)(2) = 37.996 g/mol F2

∴ Mw = Ca(CN)2 = 40.078+((12.011+14.007)(2)) = 92.114 g/mol Ca(CN)2

A. m C5H12 = ( 1.50 mol)×(72.151 g/mol) = 108.23 g C5H12

B. m F2 = (14.4 mol)×(37.996 g/mol) = 547.142 g F2

C. m Ca(CN)2 = (0.780 mol)×(92.114 g/mol) = 71.85 g Ca(CN)2

8 0
3 years ago
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