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dem82 [27]
3 years ago
12

A gas-forming reaction produces 1.15 m 3 of gas against a constant pressure of 102.0 kPa. Calculate the work done by the gas in

joules.
Chemistry
1 answer:
Aleonysh [2.5K]3 years ago
8 0

Answer:

The work done by the gas is 117,300 Joules.

Explanation:

Pressure applied on the gas , P= 102.0 kPa = 102000 Pa ( 1kPa = 1000 Pa

Change in volume of the gas ,ΔV= 1.15 m^3

Here the work is done by system so, the value of work done will be negative.

W=-P\Delta V

=W=-102000 Pa\times 1.15 m^3=117,300 J

The work done by the gas is 117,300 Joules.

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How many grams of oxygen are produced when 7.65 moles of water is decomposed
maksim [4K]

Answer:

The answer to your question is 122.4 g of O₂

Explanation:

Data

mass of O₂ = ?

moles of H₂O = 7.65

Process

1.- Write the balanced chemical reaction

                   2H₂O  ⇒  2H₂  +  O₂

2.- Convert the moles of H₂O to grams

molar mass of H₂O = 2 + 16 = 18 g

                    18 g of H₂O ---------------- 1 mol

                      x                ----------------- 7.65 moles

                      x = (7.65 x 18) / 1

                      x = 137.7 g H₂O

3.- Calculate the grams of O₂

                 36 g of H₂O -------------------- 32 g of O₂

              137.7 g of H₂O -------------------  x

                        x = (32 x 137.7) / 36

                       x = 122.4 g of O₂

 

6 0
3 years ago
If all other variables remain unchanged, what happens to the output force when the area of the input piston is doubled?
mars1129 [50]

Answer:

1250N

Explanation:

This question is based on pascal's Law.

So By Pascal's Law

 =  

therefore  =force on input piston =25N

                  = Force or weight on output person.

therefore after putting the values we get,

= (25x 1500)/30

    =1250N

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Answer:

Physical changes are changes that do not alter the identity of a substance. Chemical changes are changes that occur when one substance is turned into another substance.

Explanation:

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