2 years ago

ASAP WILL MARK BRIANLIST

1 answer:

6 0

Answer:

a,f,c,d,b

Step-by-step explanation:

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Minchanka [31]

Are you supposed to solve for the equations?

8 0

2 years ago

Arturiano [62]

This is true. you don't need to provide a counterexample

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2 years ago

Amanda [17]

Either B and D. Both seem pretty random lol

6 0

3 years ago

Naily [24]

Answer:

T₂ = 421.4 K

Step-by-step explanation:

The temperature, T, of a given mass of gas varies inversely with its Volume,V.

$T\propto \dfrac{1}{V}\\\\V_1T_1=V_2T_2$

We have,

V₁ = 98 cm³, T₁ = 28° C = (28+273) K = 301 K

V₂ = 70 cm₃

We need to find the new temperature of the gas. Using the above relation to find T₂.

$T_2=\dfrac{V_1T_1}{V_2}\\\\T_2=\dfrac{98\times 301}{70}\\\\T_2=421.4\ K$

Hence, the required temperature of the gas is 421.4 K.

4 0

2 years ago

Mariulka [41]

I think it's C, 360 degrees.

5 0

2 years ago