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Jet001 [13]
2 years ago
11

What is 2/3 divided by 2/9

Mathematics
2 answers:
Evgesh-ka [11]2 years ago
5 0

Answer- The answer is 3!

<u><em>HERE IS HOW TO FIND YOUR ANSWER:</em></u>

The process for dividing fractions is similar to that for multiplying fractions. In order to divide fractions, the fraction in the numerator is multiplied by the reciprocal of the fraction in the denominator. The reciprocal of a number a is simply 1/a . When a is a fraction, this essentially involves exchanging the position of the numerator and the denominator. The reciprocal of the fraction 3/4 would therefore be 4/3. Refer to the equations below for clarification.

serg [7]2 years ago
4 0
Your answer: 2/3/2/9 = 0.037037037037037
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I WOULD LIKE THIS SOOVED WITH A BREAK DOWN<br> (5x - 4)2= 36
Neko [114]
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3 0
3 years ago
Find the absolute extrema of the function over the region R. (In each case, R contains the boundaries.) Use a computer algebra s
algol [13]

<em>f(x, y)</em> = <em>x</em> ² - 4<em>xy</em> + 5

has critical points where both partial derivatives vanish:

∂<em>f</em>/∂<em>x</em> = 2<em>x</em> - 4<em>y</em> = 0   ==>   <em>x</em> = 2<em>y</em>

∂<em>f</em>/∂<em>y</em> = -4<em>x</em> = 0   ==>   <em>x</em> = 0   ==>   <em>y</em> = 0

The origin does not lie in the region <em>R</em>, so we can ignore this point.

Now check the boundaries:

• <em>x</em> = 1   ==>   <em>f</em> (1, <em>y</em>) = 6 - 4<em>y</em>

Then

max{<em>f</em> (1, <em>y</em>) | 0 ≤ <em>y</em> ≤ 2} = 6 when <em>y</em> = 0

max{<em>f</em> (1, <em>y</em>) | 0 ≤ <em>y</em> ≤ 2} = -2 when <em>y</em> = 2

• <em>x</em> = 4   ==>   <em>f</em> (4, <em>y</em>) = 12 - 16<em>y</em>

Then

max{<em>f</em> (4, <em>y</em>) | 0 ≤ <em>y</em> ≤ 2} = 12 when <em>y</em> = 0

max{<em>f</em> (4, <em>y</em>) | 0 ≤ <em>y</em> ≤ 2} = -4 when <em>y</em> = 2

• <em>y</em> = 0   ==>   <em>f</em> (<em>x</em>, 0) = <em>x</em> ² + 5

Then

max{<em>f</em> (<em>x</em>, 0) | 1 ≤ <em>x</em> ≤ 4} = 21 when <em>x</em> = 4

min{<em>f</em> (<em>x</em>, 0) | 1 ≤ <em>x</em> ≤ 4} = 6 when <em>x</em> = 1

• <em>y</em> = 2   ==>   <em>f</em> (<em>x</em>, 2) = <em>x</em> ² - 8<em>x</em> + 5 = (<em>x</em> - 4)² - 11

Then

max{<em>f</em> (<em>x</em>, 2) | 1 ≤ <em>x</em> ≤ 4} = -2 when <em>x</em> = 1

min{<em>f</em> (<em>x</em>, 2) | 1 ≤ <em>x</em> ≤ 4} = -11 when <em>x</em> = 4

So to summarize, we found

max{<em>f(x, y)</em> | 1 ≤ <em>x</em> ≤ 4, 0 ≤ <em>y</em> ≤ 2} = 21 at (<em>x</em>, <em>y</em>) = (4, 0)

min{<em>f(x, y)</em> | 1 ≤ <em>x</em> ≤ 4, 0 ≤ <em>y</em> ≤ 2} = -11 at (<em>x</em>, <em>y</em>) = (4, 2)

5 0
3 years ago
An ant travels at a constant rate of 30 cm every 2 minutes at what pace does the ant travel per centimeter
Rama09 [41]

Answer:

Answer: 15 cm in one minute. Step-by-step explanation: If the ant travels at 30 cm every two minutes, then divide both numbers by two to get the unit rate, which is 15 I'm per minute

6 0
3 years ago
before getting to school john has a few errands to run john has to walk 5 blocks to the galley and 9 blocks to the library befor
Serggg [28]

Answer:

  9 blocks

Step-by-step explanation:

The total of what John has already walked and the number more he must walk will be equal to the number he has to walk to get to school.

  12 + more = 5 + 9 + 7

  more = 9 + 5 + 7 - 12 . . . . . subtract 12 from both sides

  more = 9

John must walk 9 blocks more.

_____

We recognize that 5+7 = 12, so that last part of the sum totals zero.

6 0
2 years ago
Please help And be clear about you answer.
zimovet [89]
I'm not 100% sure on this. I think it's 23.
7 0
3 years ago
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