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3 years ago

15

Find the mean, median, and interquartile for the data set below. Round your answer to the nearest tenth. 27,16,8,5,19,14,22,31,1

3,5,23,16,8

1 answer:

Ray Of Light [21]3 years ago

5 0

Answer:

its 23

Step-by-step explanation:

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Find the slopes form two points (4,-6) and (-4,2)

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Answer:

y = -x – 2

Step-by-step explanation:

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3 years ago

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Smith has a garden with 40 carrots in it. They pick some carrots to feed their pet rabbit, leaving 90% of the carrots in the gar

adelina 88 [10]

Answer:the answer is 44

Step-by-step explanation: cuz 40 divided by 90%= 44

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2 years ago

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What is the partial products that results from multiplying 15 times 32

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3 years ago

Can please someone help me? The question is in the picture. Thank you

maxonik [38]

Answer:

C. $9\pi$

Step-by-step explanation:

We proceed to solve for $x$ by the Pythagorean Theorem:

$(x+1)^{2} = (x-1)^{2} + (2\cdot x - 4)^{2}$ (1)

$x^{2} + 2\cdot x + 1 = (x^{2}-2\cdot x + 1) + (4\cdot x^{2}-16\cdot x + 16)$

$x^{2} + 2\cdot x + 1 = 5\cdot x^{2}-18\cdot x + 17$

$4\cdot x^{2} -20\cdot x + 16 = 0$

$(2\cdot x)^{2} -10\cdot (2\cdot x) + 16 = 0$

$(2\cdot x -8)\cdot (2\cdot x -2) = 0$

There are two different solutions:

$x_{1} = 4$ , $x_{2} = 1$

A solution of $x$ is considered realistic when the length of every side of the triangle is a not negative number.

$x_{1} = 4$

$UV = 2\cdot (4) - 4$

$UV = 4$

$WU = 4 - 1$

$WU = 3$

$WV = 4 + 1$

$WV = 5$

$x_{2} = 1$

$UV = 2\cdot (1) - 4$

$UV = -2$

$WU = 1 - 1$

$WU = 0$

$WV = 1 + 1$

$WV = 2$

The only realistic set of solutions is for $x = 4$ , and the radius of the circle is represented by the line segment $WU$ : $r = 3$

And the area of the circle ( $A$ ) is calculated from the following formula:

$A = \pi\cdot r^{2}$

$A = \pi\cdot (9)$

$A = 9\pi$

The correct answer is C.

6 0

3 years ago

I need help with this math please

Alexus [3.1K]

In order to solve using elimination, we need to be able to get rid of one variable, so that we can solve for the other. We need to subtract these two equations given from one another, or multiply the bottom equation by a negative and add them together.

(-5x + 6y = 8) - (-5x + 4y = 2)

(-5x + 6y = 8) + (5x - 4y = -2)

0x + 2y = 6

2y = 6

y = 3

Now that we know the value of one variable, we can take that value and plug it back into one of the original equations and solve for the value of the other variable.

-5x + 6y = 8

-5x + 6(3) = 8

-5x + 18 = 8

-5x = -10

x = 2

The solution to this system of equations is (2, 3).

Hope this helps!! :)

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2 years ago

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