Answer: $53.95
Step-by-step explanation:
Given:
pounds
pounds
n= 50
Two tailed critical z-value for 90% confidence level = 1.645
Let x be the total amount of food that a cafeteria should have on hand to be 90 percent confident that it will not run out of food .
z-score =

Then, 

Foe 50 students, total amount of food = 1.079 x 50 = $53.95
hence, the cafeteria should have food of amount $53.95 so that it is be 90 percent confident that it will not run out of food.
Answer:
x^3-x^2+1
Step-by-step explanation:
u(x)=x^5-x^4+x^2
v(x)=-x^2
(u/v)(x) = (x^5-x^4+x^2) /x^2
= (x^5/x^2) - (x^4 /x^2) +(x^2/x^2)
= x^(5-2) - x ^(4-2)+ x ^(2-2)
=x^3-x^2+1
It is 1595. Put it on excel so you can better have an overview how it is done. You need 5 columns, column A-E. On column A, put 1 to 5 in rows 1 to 5. On column C, put the answers: 2, 7, 26, 101 and 400. On column D, put number 3 in all 5 rows. Back on column B, insert =sum(C1-A1) on row 1 and copy till row 5. On column E, insert =sum(B1+C1*D1) on row 1 and copy till row 5 and you will get 1595 at the end.