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2 years ago

Solve to find X. 3 ≥ -3x

Mathematics

2 answers:

lilavasa [31]2 years ago

8 0

-1 ≤ x

Step-by-step explanation:

First start with the equation:

3 ≥ -3x

divide by -3 to get x positive and singular:

-1 ≥ x

and since we divided by a negative we need to flip the sign:

-1 ≤ x would be your answer

hope this helped :)

guajiro [1.7K]2 years ago

5 0

Answer:

-1 ≤ x

Step-by-step explanation:

You just need to divide -3 on both sides.

-1 ≤ x

Note that since you are dividing by a negative number, the sign flips.

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Answer:

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Step-by-step explanation:

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2 years ago

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2 years ago

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Firdavs [7]

Answer:

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Step-by-step explanation:

We are given that $\theta_1$ is in fourth quadrant.

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$sin\theta_1$ is always negative in 4th quadrant.

Also, we know the following identity about $sin\theta$ and $cos\theta$ :

$sin^2\theta + cos^2\theta = 1$

Using \theta_1 in place of \theta:

$sin^2\theta_1 + cos^2\theta_1 = 1$

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