All categories

2 years ago

Giving brainliest if answer

Mathematics

2 answers:

Jet001 [13]2 years ago

7 0

The answer is 4.9 good luck

Sedbober [7]2 years ago

5 0

Answer:

4.9

Step-by-step explanation:

$70 times 7% = 4.9 (You can round it if you want)

You might be interested in

One evening, a restaurant served a total of 5/6 of a loaf of wheat bread and 3/10 of a loaf of white bread. How many loaves were

RideAnS [48]

Answer:

1 2/15 loaves

Step-by-step explanation:

In a restaurant:

Total Loaf of wheat bread = 5/6

Total Loaf is white bread = 3/10

The total number of loaves that were served in all =

Loaf of wheat bread + Loaf of white bread

= 5/6 + 3/10

Lowest Common Denominator = 30.

Hence:

= 25 + 9/30

= 34/30

= 1 4/30

= 1 2/15 loaves

The total number of loaves served in all = 1 2/15 loaves

4 0

3 years ago

The loudest sound, measured in decibels, is calculated using the formula L=10 log, where L is the loudness, and I is the intensi

12345 [234]

The intensity of a fire alarm that measures 125 dB loud is 268,337.29

<h3>Formula and expressions</h3>

Given the expression L=10 logI

where;

L is the loudness
I is the intensity of the sound.

Given the following parameters

L = 125dB

Substitute the given parameters into the following

L=10 logI

125 = 10logI

logI = 125/10

logI = 12.5

I = e^12.5

I = 268,337.29

Hence the intensity of a fire alarm that measures 125 dB loud is 268,337.29

Learn more on subject of formula here: brainly.com/question/657646

7 0

2 years ago

If the filling equipment is functioning properly what is the probability that the volume of oil in a randomly selected barrel wi

Sophie [7]

Answer:

$P(X>55.4)=P(\frac{X-\mu}{\sigma}>\frac{55.4-\mu}{\sigma})=P(Z>\frac{55.4-55}{0.5})=P(Z>0.8)$

$P(Z>0.8)=1-P(Z\leq 0.8)$

$P(Z>0.8)=1-0.788=0.212$

Step-by-step explanation:

Assuming this previous info : "Trucks carry barrels of crude oil from a port in Texas to a distributer in New Mexico on long trailers. Filling equipment is used to fill the barrels with the oil. When functioning properly, the actual volume of oil loaded into each barrel by the filling equipment at the port is approximately normally distributed with a mean of 55 gallons and a standard deviation of 0.5 gallons. If the mean is greater than 55.4 gallons, the filling mechanism is overfilling."

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the amount filling of a population, and for this case we know the distribution for X is given by:

$X \sim N(55,0.5)$

Where $\mu=55$ and $\sigma=0.5$

We are interested on this probability

$P(X>55.4)$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

$P(X>55.4)=P(\frac{X-\mu}{\sigma}>\frac{55.4-\mu}{\sigma})=P(Z>\frac{55.4-55}{0.5})=P(Z>0.8)$

And we can find this probability using the complement rule:

$P(Z>0.8)=1-P(Z\leq 0.8)$

And in order to find these probabilities we can use tables for the normal standard distribution, excel or a calculator.

$P(Z>0.8)=1-0.788=0.212$

8 0

3 years ago

Write the sentence as an equation.41 fewer than the quantity t times 307 is equal to n

Serhud [2]

The given statement is:

41 fewer than the quantity t times 307 is equal to n.

The equation is given by:

$307t-41=n$

3 0

1 year ago

1. The US Mint has a specification that pennies have a mean weight of 2.5g. From a sample of 37 pennies, the mean weight is foun

Evgesh-ka [11]

Answer:

the pennies does not conform to the US mints specification

Step-by-step explanation:

z = (variate -mean)/ standard deviation

z= 2.5 - 2.4991 / 0.01648 = 0.0546

we are going to check the value of z in the normal distribution table, which is the table bounded by z.

checking for z= 0.0 under 55 gives 0.0219 (value gotten from the table of normal distribution)

we subtract the value of z from 0.5 (1- (0.5+0.0219)) = 0.4781 > 0.05claim

since 0.4781 > 0.05claim, therefore, the pennies does not conform to the US mints specification

the claim state a 5% significance level whereas the calculated significance level is 47.81%. therefore, the claim should be rejected

7 0

3 years ago