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2 years ago

Giving brainliest if answer

Mathematics

2 answers:

Jet001 [13]2 years ago

7 0

The answer is 4.9 good luck

Sedbober [7]2 years ago

5 0

Answer:

4.9

Step-by-step explanation:

$70 times 7% = 4.9 (You can round it if you want)

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5^(-x)+7=2x+4 This was on plato

Setler79 [48]

Answer:

Below

I hope its not too complicated

$x=\frac{\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right)}{\ln \left(5\right)}+\frac{3}{2}$

Step-by-step explanation:

$5^{\left(-x\right)}+7=2x+4\\\\\mathrm{Prepare}\:5^{\left(-x\right)}+7=2x+4\:\mathrm{for\:Lambert\:form}:\quad 1=\left(2x-3\right)e^{\ln \left(5\right)x}\\\\\mathrm{Rewrite\:the\:equation\:with\:}\\\left(x-\frac{3}{2}\right)\ln \left(5\right)=u\mathrm{\:and\:}x=\frac{u}{\ln \left(5\right)}+\frac{3}{2}\\\\1=\left(2\left(\frac{u}{\ln \left(5\right)}+\frac{3}{2}\right)-3\right)e^{\ln \left(5\right)\left(\frac{u}{\ln \left(5\right)}+\frac{3}{2}\right)}$

$Simplify\\\\\mathrm{Rewrite}\:1=\frac{2e^{u+\frac{3}{2}\ln \left(5\right)}u}{\ln \left(5\right)}\:\\\\\mathrm{in\:Lambert\:form}:\quad \frac{e^{\frac{2u+3\ln \left(5\right)}{2}}u}{e^{\frac{3\ln \left(5\right)}{2}}}=\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}$

$\mathrm{Solve\:}\:\frac{e^{\frac{2u+3\ln \left(5\right)}{2}}u}{e^{\frac{3\ln \left(5\right)}{2}}}=\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}:\quad u=\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right)\\\\\mathrm{Substitute\:back}\:u=\left(x-\frac{3}{2}\right)\ln \left(5\right),\:\mathrm{solve\:for}\:x$

$\mathrm{Solve\:}\:\left(x-\frac{3}{2}\right)\ln \left(5\right)=\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right):\\\quad x=\frac{\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right)}{\ln \left(5\right)}+\frac{3}{2}$

3 0

3 years ago

May you help me with this question please

Lostsunrise [7]

Answer:

<em>Option C</em>

Step-by-step explanation:

Consider each of these graphs. Let us formulate an inequality for each of them, and match the one with an inequality of $x > - 14.5$ ;

$Graph 1, x > 13.5\\Graph 2, x \geq 14\\Graph 3, x > 14.5\\Graph 4, x \geq 15$

Graph 3 is the only one that matches with the inequality provided to us.

* Note that shaded circles are represented by a greater / less than or equal to, and non - shaded circles are represented by a greater / less than sign.

<em>Solution ⇒ Graph 3</em>

5 0

2 years ago

Read 2 more answers

For what values of b the relation R:{(b^2, 5), (5b, 6)} is not a function?

xenn [34]

Answer:

B=5,0.

Step-by-step explanation:

It's not that hard. It's just that it might throw you off a bit with the R and the other things. Functions if you don't remember are where the coordinates don't have the same x and y. So since the y1 and y2 are different then to make it not a function, you have to make x1 and x2. To make it that b would have to be = to 5 and 0.

6 0

3 years ago

Does anyone know the answer to this? or how to do it?

Solnce55 [7]

Answer:

( -2 , 0 ) maximum

Step-by-step explanation:

Watch the graph and point out the coordinates.

if its vertex is less that 0 or negative, then maximum.

With vertex being greater than 0 or positive, its minimum.

7 0

2 years ago

2-(-2x-4)=3x+6-x what is the answer to that?

ruslelena [56]

98--8=

Step-by-step explanation:

3 0

2 years ago