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Liono4ka [1.6K]
2 years ago
10

How do I get to this answer step by step pleaseee quickly!!!!

Mathematics
1 answer:
frutty [35]2 years ago
5 0

Answer:

Step-by-step explanation:

Direction: Opens Up

Vertex:  

(

3

,

−

4

)

Focus:  

(

3

,

−

15

4

)

Axis of Symmetry:  

x

=

3

Directrix:  

y

=

−

17

4

Select a few  

x

values, and plug them into the equation to find the corresponding  

y

values. The  

x

values should be selected around the vertex.

Tap for more steps...

x

y

1

0

2

−

3

3

−

4

4

−

3

5

0

Graph the parabola using its properties and the selected points.

Direction: Opens Up

Vertex:  

(

3

,

−

4

)

Focus:  

(

3

,

−

15

4

)

Axis of Symmetry:  

x

=

3

Directrix:  

y

=

−

17

4

x

y

1

0

2

−

3

3

−

4

4

−

3

5

0

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HELP PLEASE
Jet001 [13]

Answer:

c $11,751

Step-by-step explanation:

The function that models Alicia's car is

f(x) = 21000(0.93)^{x}

where x represents the number of years since she purchased the car.

We want to find the value of Alicia's car after 8 years.

We substitute x=8 into the formula to get:

f(8) = 21000(0.93)^{8}

f(8) = 21000(0.5596)

f(8) = 11751.218

We round to the nearest dollar to get:

f(8) =11751

The correct answer is C.

5 0
2 years ago
The range of the function f(x) = x + 5 is {7, 9}. What is the function’s domain?
mina [271]
** x + 5 = 7 x = 2 ** x + 5 = 9 x = 4 {2,4}
4 0
3 years ago
After a dreary day of rain, the sun peeks through the clouds and a rainbow forms. You notice the rainbow is the shape of a parab
Gekata [30.6K]

We can answer the first part of the question not taking intersecting function into account. The domain of y=-x^{2}+36 is all the numbers, x∈(-∞, +∞) and the range is y∈(-∞, 36]. We can observe these results with the help of a graph, as well. Since we are talking about the rainbow, the values above the ground level will make sense. In this case, we will take into account the range as it changes between 0 and 36, included and the domain between -6 and 6. Here (0;36) is the y-intercept and (-6;0) and (6;0) are the x-intercepts of the parabola.


Since in our problem, the linear function that intersects parabola is not given, we have to provide it by ourselves according to the conditions of the problem. It could be any line intersecting parabola in two points. One important point is that the y-intercept has to be no more than 36. Considering these conditions, we can set our linear function to be y=0.5x+5. We can observe the points that we included in the table (they have been given with orange dots in the graph and the table is attached below). We can see that the values of the function (values of y) are positive. Indeed, we are discussing the part of the rainbow above the ground level.


The system of equations with linear and quadratic functions has got two solutions and we can observe that result from the graph. The solutions are (-5.823; 2.088) and (5.323; 7.662). The solutions are the intersection points.

7 0
3 years ago
PLEASE SOMEONE HELP ME WITH #2
Bogdan [553]
equation : c=£1.25 for example to find out 3 cans : 3c= £1.25x3
4 0
2 years ago
A candle burned at a steady rate. After 33 minutes, the candle was 11.2 inches tall. Eighteen minutes later, it was 10.75 inches
Amiraneli [1.4K]

Answer:

9.025 inches

Step-by-step explanation:

Let the length be represented by:

L = mt+L_0

Where L is the length of candle at time t

m is the rate at which the candle is burning.

And L_0 is the initial length of the candle.

As per the question statement, let us put the given values in the equation.

11.2 = m\times 33 + L_0 .... (1)\\10.75 = m\times 51+L_0 ..... (2)

Subtracting (1) from (2):

0.45 = -18m\\\Rightarrow m = -0.025

Putting the value of m in the equation (1):

11.2 = -0.025 \times 33+L_0\\\Rightarrow L_0 = 12.025

Therefore, the equation becomes:

L = -0.025t + 12.025

Now, we have to find the height of candle after 2 hours.

2 hours mean 120 minutes.

L = -0.025 \times 120 + 12.025\\\Rightarrow L = 9.025\ inches

Therefore, the height of candle is <em>9.025 inches</em>.

3 0
2 years ago
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