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dsp73
4 years ago
11

36. GEOMETRY Write an algebraic expression to

Mathematics
1 answer:
Stels [109]4 years ago
6 0

Answer:

108 in²

Step-by-step explanation:

Area of a triangle is given as ½*base*height

The base of the given triangle = h + 6

height = h

Algebraic expression for its area = \frac{1}{2}*(h + 6)*h = \frac{1}{2}(h^2 + 6h) = \frac{h^2 + 6h}{2}

Evaluate the area if h is given as 12 inches.

Plug in the value of h into the algebraic expression:

\frac{h^2 + 6h}{2} = \frac{12^2 + 6(12)}{2}

= \frac{144 + 72}{2}

= \frac{216}{2} = 108 in^2

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Circle A: center (-4, 0) and radius 6
poizon [28]

Answer:

Circle a must be translated (x+15, y+0) and then dilated by 4/6 in order to get circle b.

3 0
3 years ago
The digit 3 in which number represents a value of 3 tens ?
Korvikt [17]

Answer:

30

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Can I get some help I think I did this wrong and I guessed :/
xz_007 [3.2K]
You'll want to first simplify the expression (2t-8)- \frac{1}{2} (9-4t)+ \frac{5}{2}}.

To do that, first distribute the - \frac{1}{2}:

(2t-8)- \frac{1}{2} (9-4t)+ \frac{5}{2}}
2t-8- \frac{9}{2} +2x+ \frac{5}{2}

From there, you may just combine like terms:

2t-8- \frac{9}{2} +2t+ \frac{5}{2}
4t-8- \frac{9}{2} + \frac{5}{2}
4t-8- \frac{4}{2}
4t-8-2
4t-10

Answer:
D. 4t - 10
8 0
3 years ago
Read 2 more answers
Solve the inequality. Enter any fractions as reduced improper fractions. 4x ≤ -2/5(6x + 6) The solution is _____​
Deffense [45]

Answer:

x≤ -3/8

Step-by-step explanation:

4x\le \:-\frac{2}{5}\left(6x+6\right)\\

Expand ;

\mathrm{Expand\:}-\frac{2}{5}\left(6x+6\right):\quad -\frac{12}{5}x-\frac{12}{5}

4x\le \:-\frac{12}{5}x-\frac{12}{5}\\\\\mathrm{Add\:}\frac{12}{5}x\mathrm{\:to\:both\:sides}\\\\4x+\frac{12}{5}x\le \:-\frac{12}{5}x-\frac{12}{5}+\frac{12}{5}x

Simplify

\frac{32}{5}x\le \:-\frac{12}{5}\\\\Multiply \:both\:sides\:by\:5\\5\times\frac{32}{5}x\le \:5\left(-\frac{12}{5}\right)\\\\Simplify\\32x\le \:-12\\\\Divide \:both\:sides\:by\:32\\\frac{32x}{32}\le \frac{-12}{32}\\\\Simplify\\x\le \:-\frac{3}{8}

6 0
4 years ago
A store sells candy at $.50, $1, $1.50, $2, and $3 per kilogram. You can see that the unit price of candies and the amount of ca
Alecsey [184]

Answer:

Constant of variation = 3

Step-by-step explanation:

Given that a store is selling different candies costing  $.50, $1, $1.50, $2, and $3 per kilogram.

As given

Amount available to buy candies = $ 3

Suppose

Unit price of candies = x

Number of candies bough = y

Constant of variation = k

As we know the unit price of candies and number of candies bought vary inversely. As the unit price would increase the the number of candies bought in available amount ($3) would decrease.

So our formula to calculate formula for constant of variation would be as shown below:

k= xy →(1

Case 1

if we take unit price x to be $0.5, then we can buy 6 kg of candies in $ 3. In this case constant of variation can be found from above equation (1) as follows:

k = (0.5)(6) = 3

Case 2

if we take unit price x to be $1, then we can buy 3 kg of candies in $ 3. In this case constant of variation can be found from above equation (1) as follows:

k = (1)(3) = 3

Case 3

if we take unit price x to be $1.5, then we can buy 2 kg of candies in $ 3. In this case constant of variation can be found from above equation (1) as follows:

k = (1.5)(2) = 3

Case 4

if we take unit price x to be $2, then we can buy 1.5 kg of candies in $ 3. In this case constant of variation can be found from above equation (1) as follows:

k = (2)(1.5) = 3

Case 4

if we take unit price x to be $3, then we can buy 1 kg of candies in $ 3. In this case constant of variation can be found from above equation (1) as follows:

k = (3)(1) = 3

So, our constant of variation is 3.

4 0
4 years ago
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