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Tcecarenko [31]
4 years ago
11

Can some plz answer this I can't figire it out 3(-3f-2)-f

Mathematics
1 answer:
velikii [3]4 years ago
6 0

9514 1404 393

Answer:

  -10f -6

Step-by-step explanation:

Maybe you want to simplify the expression ...

  3(-3f-2)-f

The distributive property is used to eliminate parentheses.

  = 3(-3f) +3(-2) -f

  = -9f -6 -f

Recognize like terms and group them together to make it easier.

  = -9f -f -6

Combine the like terms.

  = (-9 -1)f -6

  = -10f -6

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Ralph graphs line e through points (3, 6) and (12, 10) and line f through points(4, 1) and (13, 5). What can be concluded about
Lemur [1.5K]

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I think it’s b

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
6. Consider the inequality 12<-3 (x + 4). Which value of x is part of the solution set of this inequality?
Naily [24]

Answer:

-8

Step-by-step explanation:

12<-3 (x + 4)

1. distribute to the -3 to the x and 4 and should get

<em><u>-3*x = -3x</u></em>

<em><u>-3*4 = -12</u></em>

<u>12< -3x - 12</u>

2. now you get rid of the common factors which is -12 so add 12 to both sides and should get

-12+12=0

12+12=24

<u>24< -3x</u>

3. to get x by itself you will have to get rid of -3, so how to do that is divide -3 to both side and should get

-3x/-3= x

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<u>-8<x</u>

7 0
3 years ago
Find the median number of magazines purchased in a store by 4 customers. 10, 55 , 34, 21
kkurt [141]
Median of  10, 55, 34, 21

First we arrange number in ascending or descending

10, 21, 34, 55  in ascending.

Median is the middle number and this is between 21 and 34.

We find the average:

(21 + 34) /2  =  55/2  =  27.5

Median is 27.5.
8 0
3 years ago
In 2005, 0.76% of all airline flights were on-time. If we choose a simple random sample of 2000 flights, find the probability th
marissa [1.9K]

Answer:

Step-by-step explanation:

Here X no of flight that reach on time has two outcomes only and each trial is independent of the other.

Since sample size is large we approximate to normal with mean =np and variance =npq

i.e. X is N(152,19.10)

Z=\frac{x-152}{19.1} is used for converting to std normal variate

Continuity correction of 0.5 on either side of interval would be applied for x

a) P(X\geq 79%) = P(X\geq 1580)\\=P(X\geq 1579.5)\\=P(Z\geq 3.12)

=0.00

b)P(X\leq 1580)\\=P(X\leq 1580.5)\\=P(Z\leq 3.17)\\==1.00

c) p is N(0.76, sqrtpq/n)=N(0.76,0.0095)

P(p diff>0.03) =

P(Z>\frac{0.03}{0.0095} \\=P(Z>3.16)=0.00

7 0
4 years ago
HELP ASAP PLEASE!!!
fredd [130]
B. (X+4)^2 is the correct answer
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