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sveta [45]
2 years ago
9

6. Consider the inequality 12<-3 (x + 4). Which value of x is part of the solution set of this inequality?

Mathematics
1 answer:
Naily [24]2 years ago
7 0

Answer:

-8

Step-by-step explanation:

12<-3 (x + 4)

1. distribute to the -3 to the x and 4 and should get

<em><u>-3*x = -3x</u></em>

<em><u>-3*4 = -12</u></em>

<u>12< -3x - 12</u>

2. now you get rid of the common factors which is -12 so add 12 to both sides and should get

-12+12=0

12+12=24

<u>24< -3x</u>

3. to get x by itself you will have to get rid of -3, so how to do that is divide -3 to both side and should get

-3x/-3= x

24/-3= -8

<u>-8<x</u>

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Least to greatest 2.3 2 4/5 2.6
Volgvan
2.3 is smaller than 2.6: we can see it just by looking at the digits from left to right.

now, where does 2\frac{4}{5} stand?

 its fraction part is equal to

\frac{4*2}{5*2}=  \frac{8}{10}

do that means that 2\frac{4}{5}=2.8

which is bigger than 2.6

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2.3 2.6 2\frac{4}{5}




5 0
3 years ago
What are the solutions of the equation 9x4 – 2x2 – 7 = 0? Use u substitution to solve. tions of the equation 9
skelet666 [1.2K]

Answer:

Step-by-step explanation:

Let u^2=x^4\\u = x^2

Subbing in:

9u^2-2u-7=0

a = 9, b = -2, c = -7

The product of a and c is the aboslute value of -63, so a*c = 63.  We need 2 factors of 63 that will add to give us -2.  The factors of 63 are {1, 63}, (3, 21}, {7, 9}.  It looks like the combination of -9 and +7 will work because -9 + 7 = -2.  Plug in accordingly:

9u^2-9u+7u-7=0

Group together in groups of 2:

(9u^2-9u)+(7u-7)=0

Now factor out what's common within each set of parenthesis:

9u(u-1)+7(u-1)=0

We know this combination "works" because the terms inside the parenthesis are identical.  We can now factor those out and what's left goes together in another set of parenthesis:

(u-1)(9u+7)=0

Remember that u=x^2

so we sub back in and continue to factor.  This was originally a fourth degree polynomial; that means we have 4 solutions.

(x^2-1)(9x^2+7)=0

The first two solutions are found withing the first set of parenthesis and the second two are found in other set of parenthesis.  Factoring (x^2-1) gives us that x = 1 and -1.  The other set is a bit more tricky.  If

9x^2+7=0 then

9x^2=-7 and

x^2=-\frac{7}{9}

You cannot take the square root of a negative number without allowing for the imaginary component, i, so we do that:

x=±\sqrt{-\frac{7}{9} }

which will simplify down to

x=±\frac{\sqrt{7} }{3}i

Those are the 4 solutions to the quartic equation.

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3 years ago
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Answer:

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Step-by-step explanation:

We can solve this by simply knowing how many times 4 goes into 16. We can do this by writing the equation 16 ÷ 4 = 4. We now know that 4 goes into 16 4 times. By doing this we can now multiply $39.96 by 4 to get the cost of 16 bags which is $159.84.

Hope this Helps!!! :) Please comment below with some feedback!

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azamat

Answer:

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<em>Multiply both sides by 2/5</em>

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