All categories

3 years ago

A rectangle is placed around a semicircle as shown below. The width of the rectangle is 6 yd. Find the area of the shaded

Mathematics

1 answer:

morpeh [17]3 years ago

8 0

Answer:

15.48 yd squared

Step-by-step explanation:

This is because 6 yards can be used as the radius of your circle. square your radius, so 6x6 which is 36 then multiply by 3.14. You then get 113.04. Since it is a semicircle, divide it by 2. You now get 56.52. If you know your radius, you know your diameter which is 12. 12 is also the length of the rectangle so 6x12 is 72 which is the area of the rectangle. Now subtract 56.52 from 72 to get 15.48 which is the shaded region of the rectangle. So I believe that you are doing yards, so 15.48 yd squared. I hope this helps :)

You might be interested in

Write Y=4/3x-4 in slope intercept form

sergij07 [2.7K]

Answer:

Y=4/3x-4

Step-by-step explanation:

You have it in slope intercept form =)

7 0

3 years ago

10x0+10x1 what is the answer ?

sesenic [268]

Answer:

Step-by-step explanation:

10x0 is 0

10x1 is 10

6 0

2 years ago

Read 2 more answers

3 1/8 Written as Decimal

Minchanka [31]

Answer:

3.125

Hope this helps!

6 0

3 years ago

Read 2 more answers

You bicycle along a straight flat road with a safety light attached to one foot. Your bike moves at a speed of 15 km/hr and your

Viefleur [7K]

Answer:

x(t) = ( 4.167 t + 0.2 cos (2πt))

y(t) = ( 0.3 - 0.2 sin (2πt))

b) the foot have to be 3.32 rev/sec faster

Step-by-step explanation:

Given that:

the speed of the bike = 15 km/hr = 15 × 1000/3600 (m/sec) = 4.167 m/sec

radius of the circle when the foot moves = 20 cm = 0.2 m

radius of the circle above the ground = 30 cm = 0.3 m

Let assume that:

x(t) should represent the vector along the horizontal moment

y(t) should be the vector along the vertical moment

The initial component will be ( 0, 0.3)

We know that the radius of the circle is given as 0.2 m, So the vector of the circle can be written as (0.2 cos t , 0.2 sin t )

Also, the foot makes one revolution in a second, definitely the frequency of the revolution = 1 and the vector for the circle is ( 0.2 cos (2πt), -0.2 sin (2πt)), due to the fact that the foot moves clockwise.

Thus, adding all the component together ; we have:

(x(t), y(t)) = (0,0.3)+(4.167 t , 0)+(0.2 cos (2πt), -0.2 sin (2πt))

(x(t), y(t)) = (4.167 t + 0.2 cos (2πt), 0.3 - 0.2 sin (2πt))

Hence; the parametric equations are:

x(t) = ( 4.167 t + 0.2 cos (2πt))

y(t) = ( 0.3 - 0.2 sin (2πt))

The linear speed of rotation is :

15km/hr = 15 × 100, 000/3600 (cm/sec)

= 416.7 cm/sec

The rotational frequency is :

= 416.7/2πr

= 416.7/2(3.14 × 20)