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Vladimir [108]
3 years ago
7

Find the interest earned on the account$970 at 4 1/4% simple interest for 2 years​

Mathematics
1 answer:
Radda [10]3 years ago
8 0
The interest is $77.60 i think
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A student is making cookies for a bake sale. He sells 8 snickerdoodles and 12 chocolate chip
lions [1.4K]

Answer:

Snickerdoodles are 0.22$ each and chocolate chip are 0.43$ each

Step-by-step explanation:

using the information in the problem, you can make 2 separate equations: 8x+12y=6.92 and 5x+5y=3.25, let x= the cost of a snickerdoodle and y= the cost of a chocolate chip cookie.

With the 2 equations, we can isolate the y variable of the first equation and simplify which will give us y= -2/3x +6.92/12.

You can now take that equation and plug it into equation number 2:

5x+5(-2/3x + 6.92/12)=3.25.

solve that equation by multiplying 5 through the brackets: 5x-10/3x+34.6/12=3.25

add common terms: 5/3x=4.4/12

find the value of x, you will get x=0.22

plug the value of x (0.22) into one of your equations and solve for the y-value

8 0
3 years ago
Help with proofs please
alexandr402 [8]

Answer:

D. Subtraction Property of Equality

Step-by-step explanation:

Hope it helps.

8 0
2 years ago
A negative number raised to an odd power is ___ negative
Lorico [155]

Answer:

true.

Explanation:

still negative.

If a negative number is raised to an even power, the result will be positive. If a negative number is raised to an odd power, the result will be negative

4 0
3 years ago
The 44 members of the glee club are trying to raise at least $6,000 so they can compete in the state championship. They already
Anna [14]

Answer:

x=44x(6,000)x1,210

Step-by-step explanation:

7 0
2 years ago
A machine that produces a major part for an airplane engine is monitored closely. In the past, 10% of the parts produced would b
nata0808 [166]

Answer:

With a .95 probability, the sample size that needs to be taken if the desired margin of error is .04 or less is of at least 216.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

For this problem, we have that:

p = 0.1

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

With a .95 probability, the sample size that needs to be taken if the desired margin of error is .04 or less is

We need a sample size of at least n, in which n is found M = 0.04.

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.04 = 1.96\sqrt{\frac{0.1*0.9}{n}}

0.04\sqrt{n} = 0.588

\sqrt{n} = \frac{0.588}{0.04}

\sqrt{n} = 14.7

(\sqrt{n})^{2} = (14.7)^{2}

n = 216

With a .95 probability, the sample size that needs to be taken if the desired margin of error is .04 or less is of at least 216.

7 0
3 years ago
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