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Vladimir [108]
3 years ago
7

Find the interest earned on the account$970 at 4 1/4% simple interest for 2 years​

Mathematics
1 answer:
Radda [10]3 years ago
8 0
The interest is $77.60 i think
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a snail moved 1/6 foot in 1/2 hour find the speed of the snail in feet per hour write ancer in simpelest form
antoniya [11.8K]
I hope this helps you




if snail moved 1/6 foot in 1/2 hour

? foot in 1 hour



?.1/2=1.1/6


?=2.1/6


?=1/3 foot per hour
7 0
3 years ago
Read 2 more answers
7 is ten times the value of
nydimaria [60]

Answer:

0.7 or .7

Step-by-step explanation:

7 divided by 10 is 0.7

4 0
3 years ago
The ages of the winners of a cycling tournament are approximately bell-shaped. The mean age is 27.2 years, with a standard devia
elena-14-01-66 [18.8K]

Answer:

a. z-score = -1.2

b. The age 23 years old is -1.2 standard deviations below the mean

c. The age is not unusual

Step-by-step explanation:

a. Transformation to z-score

Mathematically;

z-score = (x - μ)/σ

where σ and μ are the standard deviation and the mean respectively.

From the question, x = 23, μ = 27.2 and σ = 3.5

Let’s put these into the equation;

z-score = (23-27.2)/3.5 = -1.2

b. Interpretation of result

The interpretation is that 23 years old is -1.2 standard deviations below the mean

c. Determination

The age is not unusual. This is because any z-value below -2 or above 2 is considered unusual

-1.2 is above -2 and thus it is not unusual

7 0
3 years ago
Solve.
ratelena [41]
The answer is x<6 because you have to divide 3 on both side 
4 0
3 years ago
Use the given graph. Determine the period of the function.
Ivahew [28]

Answer:

3

Step-by-step explanation:

Period of a function is the period after which the function attains the same value

in the graph attached with this problem we can see that

f(0)=1

the value of x for which function f(x) attains the value 1 again is at

x=3

f(3)=1

similarly , we see

f(6)=1 , f(9)=1

Hence we see that after every increased value of x by 3 units , we attain the same value of function . hence the period of the function is 3

6 0
3 years ago
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