The velocity function of the particle is v_{x}=2t^{2} m/s.
Since, velocity is change in position with time thus,
v_{x}=\frac{dx}{dt}
rearranging,
dx=v_{x}dt
Initial position is 1.6 m, let the final position be x,
Integrating both side,
\int_{1.6}^{x}dx=\int_{0}^{3}2t^{2}dt
x-1.6=\frac{2(3)^{3}}{3}-\frac{2(0)^{3}}{3}=18
Thus,
x=18+1.6=19.6 m
Thus, position of particle will be 19.6 m.
the answer is true because evaporates can provide an ideal speed racing surface
Answer:
7.34 meters
Explanation:
If the entire Kinetic energy is converted to Potential energy
1/2 mv^2 = mgh didvide both sides by ' m '
1/2 v^2 = gh solve for 'h'
1/2 v^2 / g = h plug in the given values , g = 9.81 m/s^2
1/2 (12)^2 / 9.81 = h = 7.34 m
Chemical Potential Energy > Electrical Energy > Light Energy + Heat Energy
Answer:
The pack has fallen 275.6 m
Explanation:
The pack is in free fall, so it is moving by uniform accelerated motion, so we can use the following suvat equation:
where, choosing upward as positive direction:
v is the final velocity
u is the initial velocity
is the acceleration of gravity
s is the vertical displacement
For the pack in this problem,
u = 0
v = -73.5 m/s
Solving for s, we find how far the packet has fallen:
And the negative sign means the direction of the displacement is downward.