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pantera1 [17]
2 years ago
12

An incompressible fluid flows at .252 m/s through a 44 diameter (circular cross section) pipe. The pipe widens to a square cross

sectional area 5.5 cm on a side. Assuming steady flow:
A. What is the speed through the square section

B. What is the flow rate in liters/minute

Work/Process is appreciated!
Physics
1 answer:
Serggg [28]2 years ago
7 0

ANSWER:

The easiest way to get a fairly accurate measure of your water flow rate is to time yourself filling up a bucket. So for example if you fill up a 10 litre bucket in 1.5 minutes, then your flow rate will be: 10/1.5 = 6.66 Litres per minute.

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A freight car moves along a friction less level railroad track at constant speed. The car is open on top. A large load of coal i
maxonik [38]

Answer:

The velocity of the freight car decreases.

Explanation:

This question is answered by the conservation of momentum principle.

When the freight car is moving at a certain speed, it has a constant momentum.

We will call this M1.

The equation for M1 will be:

M1 = Mass * Speed

Now when the coal is dumped into the freight car, the Mass increases.

Since conservation of momentum states that the momentum will remain the same. We have:

M1 = (Mass of freight + Mass of coal) * Speed

Since M1 is constant, if the mass increases, the speed had to decrease to keep the equation true.

8 0
3 years ago
Ans of this question A test charge of 1 couloumb moved from 30cm against the field of intensity 50N/c find the energy store in i
UkoKoshka [18]

Answer:

A. Zero

Explanation:

Given data,

The charge of the test charge, q = 1 C

The distance the charge moved against the filed of intensity, x = 30 cm

                                                                                                        = 0.3 m

The electric field intensity, E = 50 N/C

The energy stored in the charge at 0.3 m is given by the formula,

                                V = k q/r

Where,                        

                                     = 9 x 10⁹ Nm²C⁻²

The charge is moved from the potential V₁ to V₂ at 30 cm

Substituting the given values in the above equation

                            V₁ = 9 x 10⁹ x 30 / 0.3

                                =  1.5 x 10¹² J

And,

                            V₂ = 1.5 x 10¹² J

The energy stored in it is,

                             W = V₂ - V₁

                                  = 0

Hence, the energy stored in the charge is, W = 0        

6 0
3 years ago
Why is the physics of hssc2 so difficult?
Ivan
Could be easy for some people and hard for some people.
8 0
3 years ago
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How can you use weights of the filled cell models to determine the rate and direction of diffusion?
nikklg [1K]
Compare the initial mass to the final mass.
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3 years ago
What is a neoplasm? A. Another word for a malignant tumor B. A type of carcinoma that grows only in the mouth C. A benign swelli
Umnica [9.8K]
<h2>Answer: Any new and abnormal growth</h2>

A <u>neoplasm</u> is any <u>uncontrolled growth</u> of abnormal cells or tissues in the body.

This abnormal mass can be benign or malignant (carcinogenic).

Therefore, the correct option is D.

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3 years ago
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