Question

(2x+3)²=5.find the roots of the equation ​

Answer 1

Answer:

-2.61803398875, -0.38196601125

or

(-3±√5)/2

Step-by-step explanation:

First, expand. (2x+3)² = 4x²+12x+9=5

4x²+12x+4 = 0

Quadratic equations take the form ax²+bx+c = 0

In this case,

a = 4

b = 12

c = 4

You can solve with the equation x=(-b±√b²-4ac)/2a

Plug in:

(-12±√144-64)/8

(-12±√80)/8

(-12±√2^4×5)/8

(-12±4√5)/8

(-3±√5)/2

Final answer x = (-3±√5)/2

If you want decimal form: -2.61803398875, -0.38196601125