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Fed [463]
2 years ago
15

Through 100 ml of a one-molar sodium hydroxide solution, 896 ml (n.a.) of carbon dioxide was passed gas. Determine the mass solu

tion of salt in the resulting solution. Density of a one-molar alkali solution, take equal to 1.04 g / ml.​
Chemistry
1 answer:
Semmy [17]2 years ago
5 0
Through 100 ml of a one-molar sodium hydroxide solution, 896 ml (n.a.) of carbon dioxide was passed gas. Determine the mass solution of salt in the resulting solution. Density of a one-molar alkali solution, take equal to 1.04 g / ml.
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1. Sodium hydroxide reacts with carbon dioxide according to the equation: 2NaOH(s) + CO2(g) →
Leno4ka [110]

The limiting reagent when 5 g of NaOH and 4.4 g CO₂  allowed to react will be NaOH

<h3>What is Limiting reagent ?</h3>

The limiting reactant (or limiting reagent) is the reactant that gets consumed first in a chemical reaction and therefore limits how much product can be formed.

Given chemical equation in balanced form ;

2NaOH(s) + CO₂(g) → Na₂CO₃(s) + H₂O(l).

According to the Chemical equation ;

  • The limiting reagent when 5 g of NaOH and 4.4 g CO₂  allowed to react will be NaOH

    If 44 g CO₂ requires 80 g of NaOH, therefore, 4.4 g CO₂ will require atleast 8 g of NaOH.

    But the available quantity is 5 g NaOH. thus, NaOH is the Limiting reagent.

  • 6.625 g of Na₂CO₃ are expected to be produced 5.0 g of NaOH and 4.4 g of CO₂ are allowed to react

    As 80 g NaOH produces 106 g of Na₂CO₃.

    Therefore 5 g NaoH will produce ;

    106 / 80 x 5 = 6.625 g

Learn more about limiting reagent here ;

brainly.com/question/11848702

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