All help is much appreciated please and thank you
1 answer:
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Answer:
h(d) = (17/3249)(-d² +114d)
Step-by-step explanation:
For this purpose, it is convenient to translate and scale a quadratic parent function so it has the desired characteristics. We can start with the function ...
f(x) = 1 -x² . . . . . . . has zeros at x = ±1 and a vertex at (0, 1)
We want to horizontally expand this function by a factor of 57, so we can replace x by x/57. We want to vertically scale it by a factor of 17, so the vertex is at (0, 17). Finally, we want to translate the function 57 m to the right, which requires replacing x with x-57. After these transformations, we have ...
f(x) = 17(1 -((x-57)/57)²) = (17/3249)(-x²+114x)
Using the appropriate function name and variable, we have ...
h(d) = (17/3249)(-d² +114d)
