I need help on this ASAP with work<br> 4 and 5

You buy 4 pieces of chicken for $8.80. Write an equation that can be used to express the relationship between the total price t

Phoenix [80]

Answer:

t=$2.20c

Step-by-step explanation:

4 pieces of chicken for $8.80

Cost of 4 pieces of chicken=$8.80

$8.80/4=$2.20 for each chicken

t=$2.20c

5 0

3 years ago

Read 2 more answers

Use a flowchart to prove if the triangles in each pair of similar. NO LINKS!!!<br>

vekshin1

Answer:

Step-by-step explanation:

Start

<F = <Q Given

<GPF = <RPQ Vertically opposite angles

<FGP = <QRP A triangle has 180 degrees. 2 equal angles means the third pair must be equal

Triangle GPF ~ Triangle RPQ AAA

end

I don't see any way to make these triangles similar except by stating the statement and why it is so. There really are no yes / no choices. If you get another answer, choose it.

20

JL/LE = 90/27 Given

KL /LD = 90/27 Given

<JLK = <DLK Vertically opposite

Are the ratios equal Yes Then is the angle included Yes

Then the triangles are similar.

Are the ratios not equal No then the triangles cannot be similar

Is the angle not included Then similarity cannot be proved.

ΔJLK ≈ ΔDLK Equal Ratios and included angle === similarity

7 0

3 years ago

Read 2 more answers

The owner of a farm plants apple trees and mango trees in a ratio of 16:6. How many oak trees are planted if 198 mango trees are

BARSIC [14]

Answer:528 apple trees

Step-by-step explanation:Listen 198/6=33 so then just multiply 33x16 that equals 528 hope this helps

3 0

2 years ago

What is the height of a right triangle if its other two sides are 30 centimeters and 10 centimeters long?

Mila [183]

Answer:

Step-by-step explanation:

It depends on whether the 30 cm side is the hypotenuse, or one of the legs.

If the 30 cm side is the hypotenuse, then the third side is √(30^2-10^2) = √800 = 20√2 cm

If the 30 cm side is one of the legs, then the hypotenuse is √(30^2+10^2) = √1,000 = 10√10 cm

7 0

3 years ago

Which of the following shows that EFGH is a parallelogram for y=7 and z=9?

Anna35 [415]

Option B: $m \angle F=m \angle G=120^{\circ}$ and $m \angle E=60^{\circ}$ , so $\angle E$ is supplementary to both $\angle F$ and $\angle G$ , so EFGH is a parallelogram.

Option C: $m \angle F=m \angle G=120^{\circ}$ so EFGH is a parallelogram.

Option D: $m \angle E+m \angle G=180^{\circ}$ so EFGH is a parallelogram.

Explanation:

Option A: $m \angle E=m \angle F=60^{\circ}$ and $m \angle G=120^{\circ}$ so $\angle G$ is supplementary to both $\angle E$ and $\angle F$ , so EFGH is a parallelogram

Let us substitute $y=7$ and $z=9$ in $m \angle E=(7y+11)^{\circ}$ , $m \angle F=(17y+1)^{\circ}$ and $m \angle G=(14z-6)^{\circ}$ to determine the exact measures the angles of the parallelogram.

Substituting, we get, $m \angle E=60^{\circ}$ , $m \angle F=m \angle G=120^{\circ}$

Thus, $m \angle E\neq m \angle F$ because the measures of these angles are not equal.

Hence, Option A is not the correct answer.

Option B: $m \angle F=m \angle G=120^{\circ}$ and $m \angle E=60^{\circ}$ , so $\angle E$ is supplementary to both $\angle F$ and $\angle G$ , so EFGH is a parallelogram.

Let us substitute $y=7$ and $z=9$ in $m \angle E=(7y+11)^{\circ}$ , $m \angle F=(17y+1)^{\circ}$ and $m \angle G=(14z-6)^{\circ}$ to determine the exact measures the angles of the parallelogram.

Thus, substituting, we have, $m \angle E=60^{\circ}$ , $m \angle F=m \angle G=120^{\circ}$

Hence, Option B is the correct answer.

Option C: $m \angle F=m \angle G=120^{\circ}$ so EFGH is a parallelogram.

To determine the angles, let us substitute $z=9$ in $m \angle F=(17y+1)^{\circ}$ and $m \angle G=(14z-6)^{\circ}$

Thus, $m \angle F=m \angle G=120^{\circ}$

Since, the opposite angles of a parallelogram are equal, EFGH is a parallelogram.

Hence, Option C is the correct answer.

Option D: $m \angle E+m \angle G=180^{\circ}$ so EFGH is a parallelogram.

Let us substitute $y=7$ and $z=9$ in $m \angle E=(7y+11)^{\circ}$ , $m \angle F=(17y+1)^{\circ}$ and $m \angle G=(14z-6)^{\circ}$ to determine the exact measures the angles of the parallelogram.

Substituting, we have, $m \angle E=60^{\circ}$ , $m \angle F=m \angle G=120^{\circ}$

Adding the angles E and G, we have,

$m \angle E+m \angle G=60^{\circ}+120^{\circ}=180^{\circ}$

By the property of parallelogram, any two adjacent angles add upto 180.

Thus, the adjacent angles E and G add upto 180.

Hence, Option D is the correct answer.

3 0

3 years ago

I need help on this ASAP with work 4 and 5