Answer:
11000 J
Explanation:
Apply the formula: K = 1/2.m.v²
K = 1/2.55.20²
K = 1/2.55.400
K = 55.200
K = 11000 Joules
(35/g) = mass of 3.57kg. (9.8 for g).
<span> (35 x 0.75) = 26.25N. friction.
</span><span> (246 - 26.25) = net 219.76N. accelerating force.
</span><span> Aceleration = (f/m) = (219.76/3.57) = 61.56m/sec^2</span>
Gravitational Potential Energy (GPE) before fall = Kinetic energy on impact
GPE = mgh
GPE = 5kg x 9.8m/s^2 x 10m
GPE = 490 J
Kinetic Energy = 490 J
(This is assuming that gravitation field strength (g) is 9.8m/s^2, sometimes you may round this to 10m/s^2, therefore making the final result:
Kinetic energy = 500 J)
Orbit circumference
<span>= 2 pi *1.9*10^7 miles </span>
<span>time for orbit trip = 2.9*10^7 s </span>
<span>speed = 2 pi *1.9 / 2.9 miles/second </span>
<span>= 4.12 miles/second </span>
<span>You did not say what units </span>
<span>in miles per hour, multiply by 3600 and get </span>
<span>14,820 miles/hour</span>
