Answer:
8
Step-by-step explanation:
2log(x)=log(64)
By logarithms properties

log(x²)=log(64)
When you have log or ln in both sites, you delete them and...
x²=64
![\sqrt[]{x^{2} } =\sqrt{64} \\x=8](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7Bx%5E%7B2%7D%20%7D%20%3D%5Csqrt%7B64%7D%20%5C%5Cx%3D8)
Answer:
neither
Step-by-step explanation:
if we cube root or square root thirteen, the result will be in decimal. So thirteen is neither a perfect square nor a perfect cube
Please mark as brainliest
Yo sup??
the answer is 1 because
P(E)+P(E')=1
where E is the event and
E' is the complement of the event
Hope this helps