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2 years ago

A line, line segment, or ray that intersects a line segment at its midpoint is a segment bisector. True or fals?

Mathematics

2 answers:

Leokris [45]2 years ago

7 0

Answer:

true.

Step-by-step explanation:

hope this helps, i looked it up :)

Vlad [161]2 years ago

5 0

True
Because I did this already and got right

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Help me!!! solve the inequality!! 8 ≤ x < 6

choli [55]

Hello! the answer to this inequality is no solutions, since there are no values of x for which this can be true.

4 0

1 year ago

Help needed ASAP will give you BRAINLIEST and 5 stars

ASHA 777 [7]

Answer

Seasons.

Step-by-step explanation:

When the earth revolves around the sun it moves to different spots near the sun. This causes weather to change and the seasons.

7 0

2 years ago

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Show work please<br> \sqrt(x+12)-\sqrt(2x+1)=1

Nesterboy [21]

Answer:

$x=4$

Step-by-step explanation:

Given $\displaystyle\\\sqrt{x+12}-\sqrt{2x+1}=1$ , start by squaring both sides to work towards isolating $x$ :

$\displaystyle\\\left(\sqrt{x+12}-\sqrt{2x+1}\right)^2=\left(1\right)^2$

Recall $(a-b)^2=a^2-2ab+b^2$ and $\sqrt{a}\cdot \sqrt{b}=\sqrt{a\cdot b}$ :

$\displaystyle\\\left(\sqrt{x+12}-\sqrt{2x+1}\right)^2=\left(1\right)^2\\\implies x+12-2\sqrt{(x+12)(2x+1)}+2x+1=1$

Isolate the radical:

$\displaystyle\\x+12-2\sqrt{(x+12)(2x+1)}+2x+1=1\\\implies -2\sqrt{(x+12)(2x+1)}=-3x-12\\\implies \sqrt{(x+12)(2x+1)}=\frac{-3x-12}{-2}$

Square both sides:

$\displaystyle\\(x+12)(2x+1)=\left(\frac{-3x-12}{-2}\right)^2$

Expand using FOIL and $(a+b)^2=a^2+2ab+b^2$ :

$\displaystyle\\2x^2+25x+12=\frac{9}{4}x^2+18x+36$

Move everything to one side to get a quadratic:

$\displaystyle-\frac{1}{4}x^2+7x-24=0$

Solving using the quadratic formula:

A quadratic in $ax^2+bx+c$ has real solutions $\displaystyle x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$ . In $\displaystyle-\frac{1}{4}x^2+7x-24$ , assign values:

$\displaystyle \\a=-\frac{1}{4}\\b=7\\c=-24$

Solving yields:

$\displaystyle\\x=\frac{-7\pm \sqrt{7^2-4\left(-\frac{1}{4}\right)\left(-24\right)}}{2\left(-\frac{1}{4}\right)}\\\\x=\frac{-7\pm \sqrt{25}}{-\frac{1}{2}}\\\\\begin{cases}x=\frac{-7+5}{-0.5}=\frac{-2}{-0.5}=\boxed{4}\\x=\frac{-7-5}{-0.5}=\frac{-12}{-0.5}=24 \:(\text{Extraneous})\end{cases}$

Only $x=4$ works when plugged in the original equation. Therefore, $x=24$ is extraneous and the only solution is $\boxed{x=4}$

4 0

1 year ago

Need help with question 5) & 6)<br> TIA☺️

mart [117]

Answer:

1. a

2.d

3.b

4.e

5.c

Step-by-step explanation:

can't do question 6 though, sorry about that

7 0

2 years ago

A line passes through the point (-2,7) and had a slope of -5

Annette [7]

Answer:

a = -1

Step-by-step explanation:

The general equation for a straight line is y = mx+c, where m is the gradient/ slope, so m = -5. The first thing we need to do is find c, which we do by plugging in the x and y values that we already know: y = 7 and x = -2

7 = -5*(-2) + c

7 = 10 + c

c = 7-10 = -3

Now, we have the general equation of y = -5x -3 and we can use this to find a.

We'll treat a as x and y will be equal to 2:

2 = -5a -3

5 = -5a (Divide both sides by 5)

-a = 1 (now by -1)

a = -1

7 0

2 years ago

Read 2 more answers