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Rudik [331]
3 years ago
11

Cindy is buying a new car and wants to learn how the value of her car will change over time. Insurance actuaries predict the fut

ure value of cars using depreciation functions. One such function is applied to the car whose declining value is shown at the right. Write an exponential function for it.

Mathematics
1 answer:
lawyer [7]3 years ago
8 0

Answer:

C=10000(0.852)^t

Step-by-step explanation:

Let the exponential function be,

C=a(b)^t

Here, C = cost of the car

t = Duration or period in years

From the given table,

Two points representing cost of the car and time are (10000, 0) and (8520, 1),

For (10000, 0),

10000=a(b)^0

a = 10000

For (8520, 1)

8520 = 10000(b)^1

b=\frac{8520}{10000}

b = 0.8520

Therefore, exponential equation will be,

C=10000(0.852)^t

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Candice spent 5 1/4 hours doing her homework. Her brother, Ronald, spent 1/2 that number of hours doing his homework. How many h
Elden [556K]

Let

x-----> the number of hours that Candice spent doing her homework

y-----> the number of hours that Ronald spent doing his homework

we know that

x=5\frac{1}{4}\ hours

convert mixed number to an improper fraction

5\frac{1}{4}\ hours=\frac{5*4+1}{4}= \frac{21}{4}\ hours

so

x=\frac{21}{4}\ hours -------> equation A

y=\frac{1}{2}x ------> equation B

Substitute equation A in equation B

y=\frac{1}{2}*\frac{21}{4}=\frac{21}{8}\ hours

convert an improper fraction to a mixed number

\frac{21}{8}\ hours=2.625=2+0.625=2+\frac{5}{8}=2\frac{5}{8}\ hours

therefore

<u>the answer is the option B</u>

2\frac{5}{8}\ hours

5 0
3 years ago
Read 2 more answers
16. Solve z2 – 2z – 35 = 0 using the zero product property.
kramer
<span>z2 – 2z – 35 = 0 
2z - 2z = 35
0 = 35

No solution</span>
8 0
3 years ago
||BRAINLIEST 20 POINTS!||
Ipatiy [6.2K]

Answer:

-3+1/5

Step-by-step explanation:

4 0
2 years ago
out of some students appeared in an examination 80% passed in mathematics 75% passed in english and 5% failed in both subjects i
Advocard [28]

Answer:

5000 students appeared in the examination.

Step-by-step explanation:

We solve this question using Venn probabilities.

I am going to say that:

Event A: Passed in Mathematics

Event B: Passed in English.

5% failed in both subjects

This means that 100 - 5 = 95% pass in at least one, which means that P(A \cup B) = 0.95

80% passed in mathematics 75% passed in english

This means that P(A) = 0.8, P(B) = 0.75

Proportion who passed in both:

P(A \cap B) = P(A) + P(B) - P(A \cup B)

Considering the values we have for this problem

P(A \cap B) = P(A) + P(B) - P(A \cup B) = 0.8 + 0.75 - 0.95 = 0.6

3000 of them were passed both subjects how many students appeared in the examination?

3000 is 60% of the total t. So

0.6t = 3000

t = \frac{3000}{0.6}

t = 5000

5000 students appeared in the examination.

4 0
3 years ago
(x+5)²=81<br><br><br><br><br> need help quick
Vilka [71]
Square root each side
x-5=positive/negative 9
x=14, and -4
5 0
3 years ago
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