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Umnica [9.8K]
2 years ago
8

Tyler has 2 1/3 cups of yogurt to make smoothies. Each smoothie uses 1/3 cup of yogurt

Mathematics
1 answer:
Anika [276]2 years ago
3 0

Answer:

7 c;

Step-by-step explanation:

You might be interested in
HELP 100 POINTS The population of a city is modeled with the function P=250,000e^0.013t​, where t is the number of years since 2
erma4kov [3.2K]
Pretty difficult problem, but that’s why I’m here.
First we need to identify what we’re looking for, which is t. So now plug 450k into equation and solve for t.
450000 = 250000e^0.013t
Now to solve this, we need to remember this rule: if you take natural log of e you can remove x from exponent. And natural log of e is 1.
Basically ln(e^x) = xln(e) = 1*x
So knowing this first we need to isolate e
450000/250000 = e^0.013t
1.8 = e^0.013t
Now take natural log of both
Ln(1.8) = ln(e^0.013t)
Ln(1.8) = 0.013t*ln(e)
Ln(1.8) = 0.013t * 1
Now solve for t
Ln(1.8)/0.013 = t
T= 45.21435 years
Now just to check our work plug that into original equation which we get:
449999.94 which is basically 500k (just with an error caused by lack of decimals)
So our final solution will be in the 45th year after about 2 and a half months it will reach 450k people.
6 0
1 year ago
Because of staffing decisions, managers of the Gibson-Marion Hotel are interested in the variability in the number of rooms occu
olchik [2.2K]

Answer:

a) s^2 =30^2 =900

b) \frac{(19)(30)^2}{30.144} \leq \sigma^2 \leq \frac{(19)(30)^2}{10.117}

567.28 \leq \sigma^2 \leq 1690.224

c) 23.818 \leq \sigma \leq 41.112

Step-by-step explanation:

Assuming the following question: Because of staffing decisions, managers of the Gibson-Marimont Hotel are interested in  the variability in the number of rooms occupied per day during a particular season of the  year. A sample of 20 days of operation shows a sample mean of 290 rooms occupied per  day and a sample standard deviation of 30 rooms

Part a

For this case the best point of estimate for the population variance would be:

s^2 =30^2 =900

Part b

The confidence interval for the population variance is given by the following formula:

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}

The degrees of freedom are given by:

df=n-1=20-1=19

Since the Confidence is 0.90 or 90%, the significance \alpha=0.1 and \alpha/2 =0.05, the critical values for this case are:

\chi^2_{\alpha/2}=30.144

\chi^2_{1- \alpha/2}=10.117

And replacing into the formula for the interval we got:

\frac{(19)(30)^2}{30.144} \leq \sigma^2 \leq \frac{(19)(30)^2}{10.117}

567.28 \leq \sigma^2 \leq 1690.224

Part c

Now we just take square root on both sides of the interval and we got:

23.818 \leq \sigma \leq 41.112

5 0
3 years ago
Combine as indicated by the signs. 8-y/3y + y+2/9y - 2/6y
Taya2010 [7]

Answer:

26 + y

----------

   9y


Step-by-step explanation:

Your using parentheses here would remove a great deal of ambiguity.  Looking at your 8-y/3y + y+2/9y - 2/6y, I have interpreted it to mean:

(8-y)/3y + (y+2)/9y - (2/6)y.  For example, without parentheses, your 8-y/3y might be interpreted differently, as 8   -   y/(3y), or 8 - 1/3.

Looking at (8-y)/3y + (y+2)/9y - (2/6)y again, we see three different denominators:  3y, 9y and 6 y.  The LCD here is 9y.  Multiplying all three terms of  (8-y)/3y + (y+2)/9y - (2/6)y by the LCD, we get:

3(8-y) + (y+2) + 3y.  We must now divide this by the LCD:

3(8-y) + (y+2) + 3y

--------------------------

            9y

Next we need to perform the indicated multiplication:

24 - 3y + y + 2 + 3y

----------------------------

            9y

and then to combine like terms:

24 + 2 - 3y + y + 3y,           26 + y

----------------------------   or    -----------

              9y                             9y

7 0
3 years ago
Read 2 more answers
I’m having trouble with this
Alchen [17]

Answer:


Step-by-step explanation:

EVEN THOUGH IT SHOWS A 1 DEGREE TEMPERATURE RISE AT 4PM TO 66

THAT SHOULD NOT MATTER IT FELL A TOTAL OF 5 DEGREES FROM 3 TO 6PM  

4 0
2 years ago
Which of the following statements is true?
Inessa05 [86]

Answer: the number -5 is a real number

Real numbers are both negative and positive numbers. -5 is a negative number. Since real numbers include negative numbers, -5 is the answer.

Hope this helps!

7 0
3 years ago
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