We have by the intermediate value theorem that if a continuous function takes values both above and below zero at 2 points, there is a zero of the function in-between. We have that polynomials are continues. Let's calculate f(-6) and f(-5). f(-6)=-36 while f(-5)=-1. Thus, we cannot conclude that there is a root between them.
F(-2)=8, f(-1)=-1, so there is a flip; a zero must exist between them.
F(1)=-1, f(2)=20, so again there is a change of signs.
f(-5)=-1, f(-4)=14 so there is a root still.
We have that the only choice that does not have a root between the integers is choice a.
Answer:9
Step-by-step explanation: x+4=13
x=13-4
x=9
Answer: y = x - 2
Step-by-step explanation:
Subtract 5 from both sides.
2x-4y=-16
ax+4y=6 +
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2x+ax=-10; for x=-2,
2(-2)+a(-2)=-10
-2a=-10+4
a=-6/-2
a=3
Answer:
(9.6x10^9)-(8.9x10^9) = 7×10^8
Step-by-step explanation:
