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Lunna [17]
2 years ago
12

megan has 4 red marbles, 7 blue marbles, and 9 yellow marbles. what is the ratio of blue marbles to yellow marbles ​

Mathematics
1 answer:
11Alexandr11 [23.1K]2 years ago
4 0

Answer:

7/9

Step-by-step explanation:

Has 7 blue and 9 yellow, find the ratio of blue to yellow so just simply 7/9.

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The age difference between the two brothers is 5. 7 years later, the age of the elder brother will be 3 times bigger than the ag
saw5 [17]

Answer:

<em><u>y = 4 and x = 9</u></em>

Step-by-step explanation:

I hope this is correct

6 0
2 years ago
A person who is 1.5 meters tall casts a shadow that is 8 meters long. The distance along the ground from the person (N) to the f
neonofarm [45]
1.) 1.5m/8m= fg/32m
2.) 1.5 (32)= 8m * fg
3.) 1.5 (32)/8m= fg
4.) 6m = fg

Im pretty sure that's right
7 0
3 years ago
7x + (9x + 8) = (7x + 9x) + 8 is what property
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6 0
3 years ago
Suppose I ask you to pick any four cards at random from a deck of 52, without replacement, and bet you one dollar that at least
Tatiana [17]

Answer:

a) No, because you have only 33.8% of chances of winning the bet.

b) No, because you have only 44.7% of chances of winning the bet.

Step-by-step explanation:

a) Of the total amount of cards (n=52 cards) there are 12 face cards (3 face cards: Jack, Queen, or King for everyone of the 4 suits: clubs, diamonds, hearts and spades).

The probabiility of losing this bet is the sum of:

- The probability of having a face card in the first turn

- The probability of having a face card in the second turn, having a non-face card in the first turn.

- The probability of having a face card in the third turn, having a non-face card in the previous turns.

- The probability of having a face card in the fourth turn, having a non-face card in the previous turns.

<u><em>1) The probability of having a face card in the first turn</em></u>

In this case, the chances are 12 in 52:

P_1=P(face\, card)=12/52=0.231

<u><em>2) The probability of having a face card in the second turn, having a non-face card in the first turn.</em></u>

In this case, first we have to get a non-face card (there are 40 in the dech of 52), and then, with the rest of the cards (there are 51 left now), getting a face card:

P_2=P(non\,face\,card)*P(face\,card)=(40/52)*(12/51)=0.769*0.235=0.181

<u><em>3) The probability of having a face card in the third turn, having a non-face card in the first and second turn.</em></u>

In this case, first we have to get two consecutive non-face card, and then, with the rest of the cards, getting a face card:

P_3=(40/52)*(39/51)*(12/50)\\\\P_3=0.769*0.765*0.240=0.141

<u><em>4) The probability of having a face card in the fourth turn, having a non-face card in the previous turns.</em></u>

In this case, first we have to get three consecutive non-face card, and then, with the rest of the cards, getting a face card:

P_4=(40/52)*(39/51)*(38/50)*(12/49)\\\\P_4=0.769*0.765*0.76*0.245=0.109

With these four probabilities we can calculate the probability of losing this bet:

P=P_1+P_2+P_3+P_4=0.231+0.181+0.141+0.109=0.662

The probability of losing is 66.2%, which is the same as saying you have (1-0.662)=0.338 or 33.8% of winning chances. Losing is more probable than winning, so you should not take the bet.

b) If the bet involves 3 cards, the only difference with a) is that there is no probability of getting the face card in the fourth turn.

We can calculate the probability of losing as the sum of the first probabilities already calculated:

P=P_1+P_2+P_3=0.231+0.181+0.141=0.553

There is 55.3% of losing (or 44.7% of winning), so it is still not convenient to bet.

5 0
3 years ago
You use a juice mix to make orange juice. You combine 12 ounces of the mix with 36 ounces of water. Which is a unit rate that de
emmasim [6.3K]
12 ounces of juice mix         1 ounce of juice mix
__________________ = __________________
36 ounces of water             3 ounces of water

For every ounce of juice mix, there are 3 ounces of water. 

Hopefully, this answers your question.
5 0
3 years ago
Read 2 more answers
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