Hi there!
Recall the volume of a pyramid is:
V = 1/3(bh)
We are given the volume and side length of the base. Find the area of the base:
A = s²
A = (5xy²)² = 25x²y⁴
Plug in the solved for base:
125x³y³ = 1/3(25x²y⁴)h
To isolate for h, begin by multiplying both sides by 3:
375x³y³ = (25x²y⁴)h
Divide both sides by 25x²y⁴. Use the following exponent property:
xᵃ / xᵇ = xᵃ⁻ᵇ
Thus:
375x³y³ / 25x²4⁴ = 15x/y.
The height must be equal to:
Answer:
I think it would be 9 meters.
Step-by-step explanation:
5x2=10
28-10=18
18(divided by)2=9 meters
40 boxes would weigh would weigh 120 pounds
Answer:
x=11°
Step-by-step explanation:
-Sum of angles of a triangle should alway be 180 degrees
35+110+2+3x=180
-Add all known values
147+3x=180
-Subtract 147 from both sides
3x=33
-Isolate x by divind both sides by 3
x=11°
Answer:
i am so sorry if its wrong
Each of the triangles making up the sides and base have a base of 8 cm and a height of 6.9 cm. Then the area of the pyramid is that of 4 such triangles.
A = 4×(1/2)×b×h
A = 2×(8 cm)×(6.9 cm)
A = 110.4 cm²Step-by-step explanation:
