Answer:
Two conversion factors:
![1=\dfrac{1L}{1,000ml}\\ \\ \\ 1=\dfrac{1,000mL}{1L}](https://tex.z-dn.net/?f=1%3D%5Cdfrac%7B1L%7D%7B1%2C000ml%7D%5C%5C%20%5C%5C%20%5C%5C%201%3D%5Cdfrac%7B1%2C000mL%7D%7B1L%7D)
Explanation:
You can create two possible <em>conversion factors</em>, one to convert from mL to L, and one to convert from L to mL
<u />
<u>a) From mL to L</u>
To convert mL to L you need to multiply by a conversion factor that has mL on the denominator and L in the numerator.
Your starting point is: ![1,000mL=1L](https://tex.z-dn.net/?f=1%2C000mL%3D1L)
Then, divide both sides by 1,000mL (this will be on the denominator of the fraction);
![1,000mL=1L\\\\ \\\dfrac{1,000ml}{1,000mL}=\dfrac{1L}{1,000mL}\\ \\ \\ 1=\dfrac{1L}{1,000mL}](https://tex.z-dn.net/?f=1%2C000mL%3D1L%5C%5C%5C%5C%20%5C%5C%5Cdfrac%7B1%2C000ml%7D%7B1%2C000mL%7D%3D%5Cdfrac%7B1L%7D%7B1%2C000mL%7D%5C%5C%20%5C%5C%20%5C%5C%201%3D%5Cdfrac%7B1L%7D%7B1%2C000mL%7D)
<u>b) From L to mL</u>
Divide both sides by 1 L:
![1,000mL=1L\\\\ \\\dfrac{1,000ml}{1L}=\dfrac{1L}{1L}\\ \\ \\ 1=\dfrac{1,000mL}{1L}](https://tex.z-dn.net/?f=1%2C000mL%3D1L%5C%5C%5C%5C%20%5C%5C%5Cdfrac%7B1%2C000ml%7D%7B1L%7D%3D%5Cdfrac%7B1L%7D%7B1L%7D%5C%5C%20%5C%5C%20%5C%5C%201%3D%5Cdfrac%7B1%2C000mL%7D%7B1L%7D)
Using stoichiometry:
5.5 L of blood x (1000 mL/1L) x (15 g/100 mL) x (1 kg/1000 g) = 0.825 kg
Answer:
P₂ = 13.79 atm
Explanation:
Given data:
Initial volume = 196.0 L
Initial pressure = 1.83 atm
Final volume = 26.0 L
Final pressure = ?
Solution:
The given problem will be solved through the Boyle's law,
"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"
Mathematical expression:
P₁V₁ = P₂V₂
P₁ = Initial pressure
V₁ = initial volume
P₂ = final pressure
V₂ = final volume
Now we will put the values in formula,
P₁V₁ = P₂V₂
1.83 atm × 196.0 L = P₂× 26.0 L
P₂ = 358.68 atm. L / 26.0 L
P₂ = 13.79 atm
The answer for the question above is A. the gravitational pull of the moon on the water near the coast. The sun and and the moon are responsible for the rising and falling of the ocean tides. The gravitational pull of the moon and the sun makes the water in the oceans bulge, causing a continuous change between high and low tide.