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3 years ago

What must be part of a quantitative observation?

Chemistry

2 answers:

ziro4ka [17]3 years ago

6 0

Answer:

Quantitative observation is a method used by researchers to collect data using numerical methods such as age, weight, height. The results of this type of observation can be analyses using statistics and numerical analysis. What should be included in a quantitative observation include:

Numerical instruments
Sample
Statistical analysis
Accuracy
Reliability and validity
Bias-free/numerical results

Explanation:

Likurg_2 [28]3 years ago

4 0

Quantitative observations include numerical data. Ex: 32 degrees, 10 inches, etc.

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Consider the following multistep reaction:

chubhunter [2.5K]

The question is incomplete, here is the complete question:

Consider the following multistep reaction:

C+D⇌CD (fast)

CD+D→CD₂ (slow)

CD₂+D→CD₃ (fast)

C+3D→CD₃

Based on this mechanism, determine the rate law for the overall reaction.

Answer: The rate law for the reaction is $\text{Rate}=k'[C][D]^2$

Explanation:

Rate law is the expression which is used to express the rate of the reaction in terms of the molar concentration of reactants where each term is raised to the power their stoichiometric coefficient respectively from a balanced chemical equation.

In a mechanism of the reaction, the slow step in the mechanism determines the rate of the reaction.

For the given chemical reaction:

$C+3D\rightarrow CD_3$

The intermediate reaction of the mechanism follows:

Step 1: $C+D\rightleftharpoons CD;\text{ (fast)}$

Step 2: $CD+D\rightarrow CD_2;\text{(slow)}$

Step 3: $CD_2+D\rightarrow CD_3;\text{(fast)}$

As, step 2 is the slow step. It is the rate determining step

Rate law for the reaction follows:

$\text{Rate}=k[CD][D]$ ......(1)

As, [CD] is not appearing as a reactant in the overall reaction. So, we apply steady state approximation in it.

Applying steady state approximation for CD from step 1, we get:

$K=\frac{[CD]}{[C][D]}$

$[CD]=K[C][D]$

Putting the value of [CD] in equation 1, we get:

$\text{Rate}=k.K[C][D]^2\\\\\text{Rate}=k'[C][D]^2$

Hence, the rate law for the reaction is $\text{Rate}=k'[C][D]^2$

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