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3 years ago

2y2 + 26y + 80

Mathematics

2 answers:

vladimir1956 [14]3 years ago

7 0

D or A yea thank you yw

Illusion [34]3 years ago

3 0

A or c is the correct answer

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The slant height of the top is 5 pm and the height of the cylinder is 9m find the distance between P and Q

Mashcka [7]

Answer:The slant height of the top is 5 m, and the height of the cylinder is 9 m. Find the distance between P and Q, to the nearest cm. 0 height of small triangle.

8 0

3 years ago

Study the figure.

tia_tia [17]

Answer:

So we know the formula to calculate the area of the circular sector:

S=(r^2*π*a)/306°=

(5^2*3.14*40°)/360°= (1000*3.14) /360=8.72cm^2 so the right alternative should be the first one ,A.

Step-by-step explanation:

r - radius of the circle

a - corner of the circular sector

S - surface

4 0

4 years ago

How can you prove that csc^2(θ)tan^2(θ)-1=tan^2(θ)

Oxana [17]

Answer:

Make use of the fact that as long as $\sin(\theta) \ne 0$ and $\cos(\theta) \ne 0$ :

$\displaystyle \tan(\theta) = \frac{\sin(\theta)}{\cos(\theta)}$ .

$\displaystyle \csc(\theta) = \frac{1}{\sin(\theta)}$ .

$\sin^{2}(\theta) + \cos^{2}(\theta) = 1$ .

Step-by-step explanation:

Assume that $\sin(\theta) \ne 0$ and $\cos(\theta) \ne 0$ .

Make use of the fact that $\tan(\theta) = (\sin(\theta)) / (\cos(\theta))$ and $\csc(\theta) = (1) / (\sin(\theta))$ to rewrite the given expression as a combination of $\sin(\theta)$ and $\cos(\theta)$ .

$\begin{aligned}& \csc^{2}(\theta) \, \tan^{2}(\theta) - 1\\ =\; & \left(\frac{1}{\sin(\theta)}\right)^{2} \, \left(\frac{\sin(\theta)}{\cos(\theta)}\right)^{2} - 1 \\ =\; & \frac{\sin^{2}(\theta)}{\sin^{2}(\theta)\, \cos^{2}(\theta)} - 1\\ =\; & \frac{1}{\cos^{2}(\theta)} - 1\end{aligned}$ .

Since $\cos(\theta) \ne 0$ :

$\displaystyle 1 = \frac{\cos^{2}(\theta)}{\cos^{2}(\theta)}$ .

Substitute this equality into the expression:

$\begin{aligned}& \csc^{2}(\theta) \, \tan^{2}(\theta) - 1\\ =\; & \cdots\\ =\; & \frac{1}{\cos^{2}(\theta)} - 1 \\ =\; & \frac{1}{\cos^{2}(\theta)} - \frac{\cos^{2}(\theta)}{\cos^{2}(\theta)} \\ =\; & \frac{1 - \cos^{2}(\theta)}{\cos^{2}(\theta)}\end{aligned}$ .

By the Pythagorean identity, $\sin^{2}(\theta) + \cos^{2}(\theta) = 1$ . Rearrange this identity to obtain:

$\sin^{2}(\theta) = 1 - \cos^{2}(\theta)$ .

Substitute this equality into the expression:

$\begin{aligned}& \csc^{2}(\theta) \, \tan^{2}(\theta) - 1\\ =\; & \cdots \\ =\; & \frac{1 - \cos^{2}(\theta)}{\cos^{2}(\theta)} \\ =\; & \frac{\sin^{2}(\theta)}{\cos^{2}(\theta)}\end{aligned}$ .

Again, make use of the fact that $\tan(\theta) = (\sin(\theta)) / (\cos(\theta))$ to obtain the desired result:

$\begin{aligned}& \csc^{2}(\theta) \, \tan^{2}(\theta) - 1\\ =\; & \cdots \\ =\; & \frac{\sin^{2}(\theta)}{\cos^{2}(\theta)}\\ =\; & \left(\frac{\sin(\theta)}{\cos(\theta)}\right)^{2} \\ =\; & \tan^{2}(\theta)\end{aligned}$ .

5 0

2 years ago

Given the functions f(x) = x + 4 and g(x) = x2 − x find the value of each expression below.

dexar [7]

f(x) = x + 4

g(x) = x² - x

a) f(5)

f(5) = 5 + 4 = 9

b) g(-1)

g(-1) = (-1)² -(-1) = 1 + 1 = 2

c) f(x) = 10

10 = x + 4

x = 6

d) g(x) = 6

6 = x² - x

0 = x² - x - 6

0 = (x - 3)(x + 2)

x = 3, -2

7 0

3 years ago

95% of what number is 38

vlabodo [156]

Answer:

38 would be 95 percent of 40

6 0

3 years ago

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