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zysi [14]
2 years ago
13

How do I decease 7 by 3%​

Mathematics
2 answers:
8090 [49]2 years ago
5 0

Answer:

Percentage decrease = 7 × 3%

7 - Percentage decrease = 7-(3% x 7)= 7 - 3% x 7=7 x (1 - 3%)= (100% - 3%) × 7 = 97% x 7 = 679%

FromTheMoon [43]2 years ago
3 0

Answer:

6.79

Step-by-step explanation:

First of all, you will have to know how much is 3% of 7 in order to decrease it by that amount.

7 x 0.03 = 0.21

Now that you know the amount, you can subtract it from seven and therefore you have decreased 7 by 3%.

7 - 0.21 = 6.79

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What is the value of x in the equation 3x – 4y = 65, when y = 4? x = 23 x = 27 x=13 1/4 x=21 2/3
Vikki [24]

x=27




hope thats helpful

8 0
3 years ago
Which option below shows the graph of the function g(x) = (0.20)2 x ?
taurus [48]
The first/selected graph matches g(x)=0.2*2^x
4 0
3 years ago
Read 2 more answers
He coordinates of the vertices of a polygon are (−2, −2) , (−2, 3) , (2, 4) , (3, 1) , and (0, −2) .
Nitella [24]

Answer: The perimeter is 17.52


Step-by-step explanation:

1. You can plot the points, as you can see in the graph attached.

2. As you can see in the graph, the points are:

A(-2,-2)\\B(-2,3)\\C(2,4)\\D(3,1)\\E(0,-2)

And the lenghts <em>AB</em> and <em>EA</em> are:

AB=5

EA=2

3. To find the other lenghts, you can apply the formula for calculate the distance between two points:

distance=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}

4. Thefore, you have:

BC=\sqrt{(2-(-2))^{2}+(4-3)^{2}}=4.12\\CD=\sqrt{(2-3)^{2}+(4-1)^{2}}=3.16\\DE=\sqrt{(3-0)^{2}+(1-(-2))^{2}}=4.24

5. The perimeter is:

P=AB+CD+DE+EA\\P=5+4.12+3.16+4.24+2\\P=17.52

7 0
3 years ago
Sara, Bridget &amp; Gordon share some money in the ratio 3 : 5:5.
stellarik [79]

Answer:

let x be the total money so,

3x+5x=32

x=32/8=4

so bridget got,

5×4=£ 20

hope it helps you

Step-by-step explanation:

3 0
3 years ago
Please help me on this!
const2013 [10]

By evaluating, we will see that for x = 7 h(x) exceeds g(x).

<h3>For which value of x does h(x) first exceed g(x)?</h3>

We have:

h(x) = 2*(2)^x

g(x) = 22x - 4

Now we can evaluate both function in the different options:

h(5) = 2*(2)^5 = 64

g(5) = 22*5 - 4 = 106

We can see that for x = 5, h(x) does not exceed g(x), let's try the next one.

h(6) = 2*(2)^6 = 128

g(6) = 22*6 - 4 = 128

So, for x = 6 both functions have the same output, then for x = 7 we will see that h(x) exceeds g(x).

The correct option is B.

If you want to learn more about functions:

brainly.com/question/4025726

#SPJ1

6 0
2 years ago
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