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Leya [2.2K]
2 years ago
12

What's the circumference of a circle with a diameter of 3 inches? Use 3.14 for pi

Mathematics
1 answer:
DedPeter [7]2 years ago
3 0

Answer:

C≈18.85

Step-by-step explanation:

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8. The sum of four consecutive integers is -22.
steposvetlana [31]

Answer:

he sum of four consecutive integers is -42.

Step-by-step explanation:

5 0
3 years ago
Find the equation of the line with a slope of 4 and passing through (0,3)
Simora [160]

4x -  y + 3 =0 is the equation of the line

Step-by-step explanation:

Given:

The slope of the line  =  5

The points through with the line passes = (0,3)

To Find:

The equation of the line  =?

Solution:

The equation  y = mx + b

where m is the slope and (0,b) is the y-intercept.

The slope is given which is m = 4 and a point (0,3)

Then you can use slope-point equation

y - y_o = m(x - x_o)

where (x_o,y_o) is the given point

y - (3) = 4(x - 0)

y - 3 = 4(x)

y = 4x - 22

y - 3 = 4x

4x - y + 3 = 0

3 0
3 years ago
Read 2 more answers
What fraction of the large square is shaded? Show your work
LiRa [457]

Answer:

1/3

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
a store manager sends an email survey to customers who have registered at the store's websites. Why is this survey biased?​
Shalnov [3]

The survey is biase because it is only surveying shoppers that have registered on the website,.

8 0
3 years ago
A box contains four 75 W lightbulbs, three 60 W lightbulbs, and three burned-out lightbulbs. Two bulbs are selected at random fr
Law Incorporation [45]

Answer:

a. 0.689

b. 0.8

c. 0.427

Step-by-step explanation:

The given scenario indicates hyper-geometric experiment because because successive trials are dependent and probability of success changes on each trial.

The probability mass function for hyper-geometric distribution is

P(X=x)=kCx(N-k)C(n-x)/NCn

where N=4+3+3=10

n=2

k=4

a.

P(X>0)=1-P(X=0)

The probability mass function for hyper-geometric distribution is

P(X=x)=kCx(N-k)C(n-x)/NCn

P(X=0)=4C0(6C2)/10C2=15/45=0.311

P(X>0)=1-P(X=0)=1-0.311=0.689

P(X>0)=0.689

b.

The mean of hyper-geometric distribution is

μx=nk/N

μx=2*4/10=8/10=0.8

c.

The variance of hyper-geometric distribution is

σx²=nk(N-k).(N-n)/N²(N-1)

σx²=2*4(10-4).(10-2)/10²*9

σx²=8*6*8/900=384/900=0.427

6 0
3 years ago
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