Answer:
473 yd^3
Step-by-step explanation:
The surface area of the square base is (11 yd)^2, or 121 yd^2.
The surface area of one of the slanting sides of the pyramid is
A = (1/2)(b)(h), which comes to A = (1/2)(11 yd)(16 yd) = 88 yd^2.
Thus, four such sides have a combined surface area of 352 yd^2.
Combining the surface areas of the slanting sides with the base area yields 473 yd^3
It’s the second one, 65.4
V=1
6πd3=1
6·π·53≈ 65.44985in³
Since the given line is <span>ll to the req. line, so
</span>x-2y=62y = x - 6
y = (1/2)x - 3
slope = 1/2
equation of the req. line is
y - y1 = m(x - x1)
y - 6 = 1/2(x - 1)
2(y - 6) = 1(x - 1)
2y - 12 = x - 1
2y = x -1 + 12
2y = x + 11
y = (1/2)x + 11/2
The answer is A! The simplified equation would be 6x-6+8 and then it simplifies to 6x+2!
Answer:
A. 1
Step-by-step explanation:
The relative frequency is calculated by dividing the frequency of respective class to the total frequency. i.e R.f=f/∑f.
Hence, the relative frequencies can never be add up to total number of observations because it is computed from taking the proportion of frequency and total number of observation. The relative frequencies thus add up to 1.
For example we are given the frequencies for 3 classes as 6,4,2 and computed relative frequencies of these 3 classes are 6/12, 4/12 and 2/12.
Now adding these three relative frequencies 6/12+4/12+2/12=6+4+2/12=12/12=1.
Thus, the relative frequencies add up to 1.
