Answer:
Step-by-step explanation:
Can the sides of a triangle have lengths 5, 8, and 11?
We can't see what you're trying to say.
Answer:
y = - 3
Step-by-step explanation:
3(-2x+5)=-x-5
-6x+15=-x-5
-5x=-20
x=4
y=-2(4)+5
y=-3
<h3>
Answer: choice C) 15</h3>
Simplify the left side to get
2(4+x)+(13+x)
2(4)+2(x) +13+x
8+2x+13+x
3x+21
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So the original equation
2(4+x)+(13+x) = 3x+k
turns into
3x+21 = 3x+k
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Subtract 3x from both sides
3x+21 = 3x+k
3x+21-3x = 3x+k-3x
21 = k
k = 21
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If k = 21, then the original equation will have infinitely many solutions. This is because we will end up with 3x+21 on both sides, leading to 0 = 0 after getting everything to one side. This is a true equation no matter what x happens to be.
If k is some fixed number other than 21, then there will be no solutions. This equation is inconsistent (one side says one thing, the other side says something different). If k = 15, then
3x+21 = 3x+k
3x+21 = 3x+15
21 = 15 .... subtract 3x from both sides
The last equation is false, so there are no solutions here.
note: if you replace k with a variable term, then there will be exactly one solution.
quotient is 98 1/2
<u> 0098 </u> 14/28
28 | 2758
<u> 252 </u> * 9 x 28
238
<u> 224 </u> * 8 x 28
14
2758 ÷ 28 = 98 14/28 simplified to 98 1/2
